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Is there a function I can call that returns a list of ascending numbers? I.e., function(10) would return [0,1,2,3,4,5,6,7,8,9]?
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Python List sort() - Sorts Ascending or Descending List. The list. sort() method sorts the elements of a list in ascending or descending order using the default < comparisons operator between items. Use the key parameter to pass the function name to be used for comparison instead of the default < operator.
Python comes with a direct function range() which creates a sequence of numbers from start to stop values and print each item in the sequence. We use range() with r1 and r2 and then convert the sequence into list.
In Python, a list is created by placing elements inside square brackets [] , separated by commas. A list can have any number of items and they may be of different types (integer, float, string, etc.).
You want range().
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range(10) is built in.
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If you want an iterator that gives you a series of indeterminate length, there is itertools.count(). Here I am iterating with range() so there is a limit to the loop.
>>> import itertools
>>> for x, y in zip(range(10), itertools.count()):
... print x, y
...
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
Later: also, range() returns an iterator, not a list, in python 3.x. in that case, you want list(range(10)).
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