I have some SQL code which generates random numbers using the following technique:
DECLARE @Random1 INT, @Random2 INT, @Random3 INT, @Random4 INT, @Random5 INT, @Random6 INT, @Upper INT, @Lower INT
---- This will create a random number between 1 and 49
SET @Lower = 1 ---- The lowest random number
SET @Upper = 49; ---- The highest random number
with nums as (
select @lower as n
union all
select nums.n+1
from nums
where nums.n < @Upper
),
randnums as
(select nums.n, ROW_NUMBER() over (order by newid()) as seqnum
from nums
)
select @Random1 = MAX(case when rn.seqnum = 1 then rn.n end),
@Random2 = MAX(case when rn.seqnum = 2 then rn.n end),
@Random3 = MAX(case when rn.seqnum = 3 then rn.n end),
@Random4 = MAX(case when rn.seqnum = 4 then rn.n end),
@Random5 = MAX(case when rn.seqnum = 5 then rn.n end),
@Random6 = MAX(case when rn.seqnum = 6 then rn.n end)
from randnums rn;
select @Random1, @Random2, @Random3, @Random4, @Random5, @Random6
My question is how random is this number generation? and is there another way to do this which is more "random".
I am using:
Microsoft SQL Server 2008 (SP3) - 10.0.5512.0 (X64) Aug 22 2012 19:25:47 Copyright (c) 1988-2008 Microsoft Corporation Developer Edition (64-bit) on Windows NT 6.1 <X64> (Build 7601: Service Pack 1)
The problem with most solutions is you'll end up with values like this: 14,29,8,14,27,27
I cannot have duplicate numbers!
In SQL Server, you can use the NEWID() function to create a unique value. More specifically, it's an RFC4122-compliant function that creates a unique value of type uniqueidentifier. The value that NEWID() produces is a randomly generated 16-byte GUID (Globally Unique IDentifier).
You could use CHAR(ROUND(RAND() * 93 + 33, 0)) to generate a random character.
Here is how you can use the RAND function to generate a set of unique random numbers in Excel: In a column, use =RAND() formula to generate a set of random numbers between 0 and 1.
I guess you could do something like this much simpler and much easier
DECLARE @Upper INT;
DECLARE @Lower INT;
SET @Lower = 1; /* -- The lowest random number */
SET @Upper = 49; /* -- The highest random number */
SELECT @Lower + CONVERT(INT, (@Upper-@Lower+1)*RAND());
For getting a random number without repetition, this will do the job
WITH CTE
AS
(
SELECT randomNumber, COUNT(1) countOfRandomNumber
FROM (
SELECT ABS(CAST(NEWID() AS binary(6)) %49) + 1 randomNumber
FROM sysobjects
) sample
GROUP BY randomNumber
)
SELECT TOP 5 randomNumber
FROM CTE
ORDER BY newid()
To set the highest limit, you can replace 49 with your highest limit number.
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