Say I have these rows,
InstrumentID
547
698
708
InstrumentID is not autogenerated column.
Say if I pass the parameter in procedure as 698, I should get previous value as 547 and next value as 708. How do I do this efficiently in SQL?
I have this procedure but it is not efficient (and not correct).
Alter PROCEDURE GetNextAndPreviousInsturmentID
(
@InstrumentID varchar(14),
@PreviousInstrumentID varchar(14) OUT,
@NextInstrumentID varchar(14) OUT
)
AS
BEGIN
Declare @RowNum int = 0
Select @RowNum = ROW_NUMBER() Over (Order by Cast(@InstrumentID as decimal(18))) From Documents Where InstrumentID = @InstrumentID
;With normal As
(
Select ROW_NUMBER() Over (Order by Cast(@InstrumentID as decimal(18))) as RowNum, Cast(InstrumentID as decimal(18)) as InstrumentID
From Documents
)
Select @PreviousInstrumentID = InstrumentID From normal
Where RowNum = @RowNum - 1
Select @NextInstrumentID = InstrumentID From normal
Where RowNum = @RowNum + 1
END
GO
SQL Server LAG() is a window function that provides access to a row at a specified physical offset which comes before the current row. In other words, by using the LAG() function, from the current row, you can access data of the previous row, or the row before the previous row, and so on.
For example, by using the LEAD() function, from the current row, you can access data of the next row, or the row after the next row, and so on. The LEAD() function can be very useful for comparing the value of the current row with the value of the following row.
1) You can use MAX or MIN along with OVER clause and add extra condition to it. The extra condition is "ROWS BETWEEN 1 PRECEDING AND 1 PRECEDING" which will fetch previous row value. Check this: SELECT *,MIN(JoiningDate) OVER (ORDER BY JoiningDate ROWS BETWEEN 1 PRECEDING AND 1 PRECEDING) AS EndDate.
1 Answer. ORDER BY id ASC; In the above query, we used subquery with the TOP clause that returns the table with the last 5 records sorted by ID in descending order. Again, we used to order by clause to sort the result-set of the subquery in ascending order by the ID column.
Here is a simpler solution, still it's more efficient
SELECT P.PreviousID, N.NextID
FROM
(SELECT MAX(D.InstrumentID) PreviousID
FROM Documents D
WHERE InstrumentID < @InstrumentID) P
CROSS JOIN
(SELECT MIN(D.InstrumentID) NextID
FROM Documents D
WHERE InstrumentID > @InstrumentID) N
Try this:
Alter PROCEDURE GetNextAndPreviousInsturmentID
(
@InstrumentID varchar(14),
@PreviousInstrumentID varchar(14) OUT,
@NextInstrumentID varchar(14) OUT
)
AS
BEGIN
Declare @Ids TABLE(Id varchar(14))
;With normal As
(
--Numerate our rows
Select ROW_NUMBER() Over (Order by Cast(Documents.InstrumentID as decimal(18)) as RowNumber,
Documents.InstrumentID
From Documents
)
--Insert three rows from our table with our id and previos/next id
INSERT INTO @Ids(Id)
SELECT TOP(3) normal.InstrumentID
FROM normal
WHERE RowNumber >=
(
SELECT RowNumber - 1
FROM normal
WHERE normal.InstrumentID = @InstrumentID
)
ORDER BY normal.RowNumber
--select next and previos ids
SELECT @PreviousInstrumentID = Min(CAST(Id as decimal(18))),
@NextInstrumentID = MAX(CAST(Id as decimal(18)))
FROM @Ids
END
GO
In MS SQL 2012 we have new window functions like FIRST_VALUE and LAST_VALUE, unfortunately in sql 2008 these functions are missing.
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