Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Fixing phase unwrapping errors in Numpy

I have a series of unwrapped phases, with some unwrapping errors that consist of a jump of +/- a multiple of Pi:

import numpy
a = numpy.array([0.5, 1.3, 2.4, 10.3, 10.8, 10.2, 7.6, 3.2, 2.9])

In this example there is a first jump of 2 cycles between 2.4 and 10.3, and a jump of -1 cycle between 7.6 and 3.2. I want to remove the jumps. The catch is that when you remove a jump, you need to increase or decrease the rest of the series accordingly, not just the value where the jump occurs.

Is there a cleaner way (no/less loops, faster) of doing this:

jumpsexist = 1
while jumpsexist:
    # Look for absolute differences greater than Pi
    jump = numpy.abs((numpy.roll(a,-1) -a)) > numpy.pi
    if jump[:-1].any():
        # Find the index of the first jump
        jumpind = numpy.argmax(jump) + 1
        # Calculate the number of cycles in that jump
        cycles = ((a[jumpind] - a[jumpind- 1]) / numpy.pi).astype("Int8")
        # Remove the cycles
        a[jumpind:] -= cycles * numpy.pi
    else:
        break
like image 686
Benjamin Avatar asked Apr 12 '12 14:04

Benjamin


2 Answers

NumPy offers the function numpy.unwrap() for phase unwrapping. With the default parameter values, it will correct an array of phases modulo 2π such that all jumps are less than or equal to π:

>>> a = numpy.array([0.5, 1.3, 2.4, 10.3, 10.8, 10.2, 7.6, 3.2, 2.9])
>>> numpy.unwrap(a)
array([ 0.5       ,  1.3       ,  2.4       ,  4.01681469,  4.51681469,
        3.91681469,  1.31681469,  3.2       ,  2.9       ])
like image 84
Sven Marnach Avatar answered Oct 09 '22 02:10

Sven Marnach


How about this:

import numpy as np 
a = np.array([0.5, 1.3, 2.4, 10.3, 10.8, 10.2, 7.6, 3.2, 2.9])
d = np.diff(a)/np.pi
b = np.empty_like(a)
b[0] = a[0]
b[1:] = a[1:]-(np.floor(np.abs(d))*np.sign(d)).cumsum()*np.pi

which gives:

In [40]: print a
[  0.5   1.3   2.4  10.3  10.8  10.2   7.6   3.2   2.9]

In [41]: print b
[ 0.5         1.3         2.4         4.01681469  4.51681469  3.91681469
  1.31681469  0.05840735 -0.24159265]

Here d holds the signed magntiude of the "jumps", and cumulative summation of the appropriately truncated "jumps" is the mulitple of pi which needs to be removed/added to each sucessive element of the series.

Is that what you meant?

like image 2
talonmies Avatar answered Oct 09 '22 02:10

talonmies