Given a month in numeric form (e.g., 2 for February), how do you find the first month of its respective quarter (e.g., 1 for January)?
I read through the datetime
module documentation and the Pandas documentation of their datetime functions, which ought to be relevant, but I could not find a function that solves this problem.
Essentially, what I am trying to understand is how I could produce a function like the one below that, given month x, outputs the number corresponding to the first month of x's quarter.
>> first_month_quarter(5)
4
Notice how it uses the formula quarter = (moy + 2) / 3 . Therefore, to find the starting month of a quarter, we just need to rearrange it in terms of moy - moy = quarter * 3 - 2 .
It's not so pretty, but if speed is important a simple list lookup slaughters math
:
def quarter(month, quarters=[None, 1, 1, 1, 4, 4, 4,
7, 7, 7, 10, 10, 10]):
"""Return the first month of the quarter for a given month."""
return quarters[month]
A timeit
comparison suggests this is about twice as fast as TigerhawkT3's mathematical approach.
Test script:
import math
def quarter(month, quarters=[None, 1, 1, 1, 4, 4, 4,
7, 7, 7, 10, 10, 10]):
"""Return the first month of the quarter for a given month."""
return quarters[month]
def firstMonthInQuarter1(month):
return (month - 1) // 3 * 3 + 1
def firstMonthInQuarter2(month):
return month - (month - 1) % 3
def first_month_quarter(month):
return int(math.ceil(month / 3.)) * 3 - 2
if __name__ == '__main__':
from timeit import timeit
methods = ['quarter', 'firstMonthInQuarter1', 'firstMonthInQuarter2',
'first_month_quarter']
setup = 'from __main__ import {}'.format(','.join(methods))
results = {method: timeit('[{}(x) for x in range(1, 13)]'.format(method),
setup=setup)
for method in methods}
for method in methods:
print '{}:\t{}'.format(method, results[method])
Results:
quarter: 3.01457574242
firstMonthInQuarter1: 4.51578357209
firstMonthInQuarter2: 4.01768559763
first_month_quarter: 8.08281871176
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