Print 5 items in a row on separate lines for a list?

Question

I have a list of unknown number of items, let's say 26. let's say

list=['a','b','c','d','e','f','g','h',
'i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

How to print like this:

abcde

fghij

klmno

pqrst

uvwxy

z

? Thank you very much. Attempt:

    start = 0
    for item in list:
        if start < 5:
            thefile.write("%s" % item)
            start = start + 5
        else:
            thefile.write("%s" % item)
            start = 0

Answer 1

for i, a in enumerate(A):
    print a, 
    if i % 5 == 4: 
        print "\n"

Another alternative, the comma after the print means there is no newline character

Answer 2

You can simple do this by list comprehension: "\n".join(["".join(lst[i:i+5]) for i in xrange(0,len(lst),5)]) the xrange(start, end, interval) here would give a list of integers which are equally spaced at a distance of 5, then we slice the given list in to small chunks each with length of 5 by using list slicing.

Then the .join() method does what the name suggests, it joins the elements of the list by placing the given character and returns a string.

lst = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

print "\n".join(["".join(lst[i:i+5]) for i in xrange(0,len(lst),5)])

>>> abcde
    fghij
    klmno
    pqrst
    uvwxy
    z