Find the line number where a specific word appears with "grep" [closed]

Question

Is grep capable of providing the line number on which the specified word appears?

Also, is possible to use grep to search for a word starting from some certain line downward?

Answer 1

Use grep -n to get the line number of a match.

I don't think there's a way to get grep to start on a certain line number. For that, use sed. For example, to start at line 10 and print the line number and line for matching lines, use:

sed -n '10,$ { /regex/ { =; p; } }' file 

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To get only the line numbers, you could use

grep -n 'regex' | sed 's/^\([0-9]\+\):.*$/\1/' 

Or you could simply use sed:

sed -n '/regex/=' file 

Combining the two sed commands, you get:

sed -n '10,$ { /regex/= }' file 

Answer 2

You can call tail +[line number] [file] and pipe it to grep -n which shows the line number:

tail +[line number] [file] | grep -n /regex/ 

The only problem with this method is the line numbers reported by grep -n will be [line number] - 1 less than the actual line number in [file].