Pass parameter to an awk script file

Question

If I want to pass a parameter to an awk script file, how can I do that ?

#!/usr/bin/awk -f  {print $1} 

Here I want to print the first argument passed to the script from the shell, like:

bash-prompt> echo "test" | ./myawkscript.awk hello bash-prompt> hello 

Answer 1

In awk $1 references the first field in a record not the first argument like it does in bash. You need to use ARGV for this, check out here for the offical word.

Script:

#!/bin/awk -f  BEGIN{     print "AWK Script"     print ARGV[1] } 

Demo:

$ ./script.awk "Passed in using ARGV" AWK Script Passed in using ARGV