To create the new column 'Max', use df['Max'] = df. idxmax(axis=1) . To find the row index at which the maximum value occurs in each column, use df. idxmax() (or equivalently df.
Pandas DataFrame max() Method The max() method returns a Series with the maximum value of each column. By specifying the column axis ( axis='columns' ), the max() method searches column-wise and returns the maximum value for each row.
To find the maximum value of each row, call the max() method on the Dataframe object with an argument axis = 1.
Find Maximum Element in Pandas DataFrame's RowIf the axis equals to 0, the max() method will find the max element of each column. On the other hand, if the axis equals to 1, the max() will find the max element of each row.
Assuming df
has a unique index, this gives the row with the maximum value:
In [34]: df.loc[df['Value'].idxmax()]
Out[34]:
Country US
Place Kansas
Value 894
Name: 7
Note that idxmax
returns index labels. So if the DataFrame has duplicates in the index, the label may not uniquely identify the row, so df.loc
may return more than one row.
Therefore, if df
does not have a unique index, you must make the index unique before proceeding as above. Depending on the DataFrame, sometimes you can use stack
or set_index
to make the index unique. Or, you can simply reset the index (so the rows become renumbered, starting at 0):
df = df.reset_index()
df[df['Value']==df['Value'].max()]
This will return the entire row with max value
I think the easiest way to return a row with the maximum value is by getting its index. argmax()
can be used to return the index of the row with the largest value.
index = df.Value.argmax()
Now the index could be used to get the features for that particular row:
df.iloc[df.Value.argmax(), 0:2]
The country and place is the index of the series, if you don't need the index, you can set as_index=False
:
df.groupby(['country','place'], as_index=False)['value'].max()
Edit:
It seems that you want the place with max value for every country, following code will do what you want:
df.groupby("country").apply(lambda df:df.irow(df.value.argmax()))
Use the index
attribute of DataFrame
. Note that I don't type all the rows in the example.
In [14]: df = data.groupby(['Country','Place'])['Value'].max()
In [15]: df.index
Out[15]:
MultiIndex
[Spain Manchester, UK London , US Mchigan , NewYork ]
In [16]: df.index[0]
Out[16]: ('Spain', 'Manchester')
In [17]: df.index[1]
Out[17]: ('UK', 'London')
You can also get the value by that index:
In [21]: for index in df.index:
print index, df[index]
....:
('Spain', 'Manchester') 512
('UK', 'London') 778
('US', 'Mchigan') 854
('US', 'NewYork') 562
Sorry for misunderstanding what you want, try followings:
In [52]: s=data.max()
In [53]: print '%s, %s, %s' % (s['Country'], s['Place'], s['Value'])
US, NewYork, 854
In order to print the Country and Place with maximum value, use the following line of code.
print(df[['Country', 'Place']][df.Value == df.Value.max()])
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