filtering file from the result of find command

Question

I want to look for a particular pattern in a directory of files and want to exclude certain patterns while the result is displayed.

I use the following command

find . -type f -exec grep -il 'foo' {} \; | find . -not -name "*.jar" -not -name "*.gz" -not -name "*.log" 2>/dev/null

when the result is displayed, I see the following error message

find: grep terminated by signal 13

Can someone please guide me as to why this error message is there and if there is a better command to use for getting the desired result (basically excluding jar files or log files or some other type of files from the result set)?

Answer 1

I think you're trying to use find as grep in the second half of that pipeline; find doesn't work like that. What you should do is have it all in one command:

find . -type f -not -name "*.jar" -not -name "*.gz" -not -name "*.log" -exec grep -il 'foo' {} + 2>/dev/null

Or

find . -type f -not -name "*.jar" -not -name "*.gz" -not -name "*.log" -exec grep -qi 'foo' {} \; -print 2>/dev/null

Or let grep traverse the tree itself and filter the names after (using grep, not find):

grep -irl foo . | grep -v -e '\.jar$' -e '\.gz$' -e '\.log$'

Answer 2

find . | grep -v "jar$" | grep -v "log$" | grep -v "gz$"