I have a list such as below, where the 1 column is position and the other columns aren't important for this question.
1 1 2 3 4 5
2 1 2 3 4 5
5 1 2 3 4 5
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
I want to fill in the gaps such that the list is continuous and it reads
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
I am familiar with awk and shell scripts, but whatever way it can be done is fine with me. Thanks for any help..
this one-liner may work for you:
awk '$1>++p{for(;p<$1;p++)print p" 0 0 0 0 0"}1' file
with your example:
kent$ echo '1 1 2 3 4 5
2 1 2 3 4 5
5 1 2 3 4 5
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5'|awk '$1>++p{for(;p<$1;p++)print p" 0 0 0 0 0"}1'
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
You can use the following awk one-liner:
awk '{b=a;a=$1;while(a>(b++)+1){print(b+1)," 0 0 0 0 0"}}1' input.file
Tested with here-doc input:
awk '{b=a;a=$1;while(a>(b++)+1){print(b+1)," 0 0 0 0 0"}}1' <<EOF
1 1 2 3 4 5
2 1 2 3 4 5
5 1 2 3 4 5
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
EOF
the output is as follows:
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
Explanation:
On every input line b
is set to a
where a
is the value of the first column. Because of the order in which b
and a
are initialized, b
can be used in a while
loop that runs as long as b < a-1
and inserts the missing lines, filled up with zeros. The 1
at the end of the script will finally print the input line.
This is only for fun:
join -a2 FILE <(seq -f "%g 0 0 0 0 0" $(tail -1 FILE | cut -d' ' -f1)) | cut -d' ' -f -6
produces:
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
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