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extracting a variable from json output then debug and register the outout with ansible

Tags:

json

ansible

Hi I have a problem of getting one of the variables extracted from a json output after doing a curl to be parsed and registered back to ansible

Playbook:

- name: debug stdout
  debug: 
    msg: "{{ result.stdout | from_json }}"
  register: dataresult

- name: debug fact
  debug:
    msg: "{{ dataresult.data.start_time_string }}"

output :

TASK [backup_api : debug stdout] 
***********************************************
task path: /home/ansible/cm-dha/roles/backup_api/tasks/main.yml:36
ok: [127.0.0.1] => {
   "msg": {
       "data": [
           {
            "backup_id": 40362,
            "certified": null,
            "instance_id": 148,
            "start_time": 1506985211,
            "start_time_string": "10/03/2017 03:00:11 am"
           }
       ],
      "timestamp": 1507022232
   }

}

error:

fatal: [127.0.0.1]: FAILED! => { "failed": true, "msg": "the field 'args' has an invalid value, which appears to include a variable that is undefined. The error was: 'dict object' has no attribute 'data'\n\nThe error appears to have been in '/home/ansible/cm-dha/roles/backup_api/tasks/main.yml': line 48, column 5, but may\nbe elsewhere in the file depending on the exact syntax problem.\n\nThe offending line appears to be:\n\n\n - name: debug fact\n ^ here\n"

The error is happening when trying to extract the value start_time_string

so how to do it probably as I tried too many things like using with_items, with_dict , simulating the data[] output to debug and even doing a json query but without success

so any help here?

like image 343
yousef Avatar asked Oct 03 '17 09:10

yousef


1 Answers

Don't use debug to assign facts, use set_fact instead:

- name: debug stdout
  set_fact: 
    dataresult: "{{ result.stdout | from_json }}"

- name: debug fact
  debug:
    msg: "{{ dataresult.data[0].start_time_string }}"
like image 135
Konstantin Suvorov Avatar answered Sep 22 '22 01:09

Konstantin Suvorov