I have this :
template<class T, class U>
class A
{
template<size_t N>
void BindValues();
}
template<class T, class U>
template<size_t N>
inline void A<T, U>::BindValues()
{
conn->setValue<N-1>( std::get<N-1>(m_Tuple) );
BindValues<N-1>(conn);
}
template<class T, class U>
template<>
inline void A<T, U>::BindValues<1>()
{
conn->setValue<0>( std::get<0>(m_Tuple) );
}
My Compile error is:
invalid explicit specialization before '>' token
enclosing class templates are not explicitly specialized
template-id BindValues<1> for void A<T, U>::BindValues() does not match any template declaration
Unfortunately a template
method inside a template
class cannot be specialized just based on template
argument of method.
You need to specialize the template class
also. In other words, the member method specialization should be a complete specialization with respect to class template
(i.e. <T,U>
) params as well as the member template
params (i.e. <size_t>
).
For example, you may have to specialize something like this (demo):
template<> // <------ you have to specialize class also
template<>
inline void A<int, double>::BindValues<1>() // <-------- see A<T,U>
{
...
}
What you are trying to do is partial template specialization for a function, which is not allowed.
You can define the template function on N
for a template specialization of A (e.g. A<int, int>::BindValues<N>()
) but the other way around is not allowed.
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