Execute a file with arguments in Python shell

Question

I would like to run a command in Python Shell to execute a file with an argument.

For example: execfile("abc.py") but how to add 2 arguments?

Answer 1

try this:

import sys sys.argv = ['arg1', 'arg2'] execfile('abc.py') 

Note that when abc.py finishes, control will be returned to the calling program. Note too that abc.py can call quit() if indeed finished.