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If a class inherits from another and overrides a virtual function, how must the exception-specification for the derived (overridden) function be related to the base function?
Is that is must be at least as restrictive? right? or others?
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Because virtual functions are called only for objects of class types, you cannot declare global or static functions as virtual . The virtual keyword can be used when declaring overriding functions in a derived class, but it is unnecessary; overrides of virtual functions are always virtual.
If you don't override a pure virtual function in a derived class, that derived class becomes abstract: class D2 : public Base { // no f1: fine.
It is not mandatory for the derived class to override (or re-define the virtual function), in that case, the base class version of the function is used. A class may have virtual destructor but it cannot have a virtual constructor.
Exception specifications are a C++ language feature that indicate the programmer's intent about the exception types that can be propagated by a function. You can specify that a function may or may not exit by an exception by using an exception specification.
Yes, it must be at least as restrictive (§15.4/3):
If a virtual function has an exception-specification, all declarations, including the definition, of any function that overrides that virtual function in any derived class shall only allow exceptions that are allowed by the exception-specification of the base class virtual function.
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