I have already looked at a couple questions on this, specifically Overloading operator<<: cannot bind lvalue to ‘std::basic_ostream<char>&&’ was very helpful. It let me know that my problem is I'm doing something that c++11 can't deduce the type from.
I think a big part of my problem is that the instantiated class I'm working with, is templated, but originally obtained from a pointer to a non-template base class. This is something I did advised from another stackoverflow.com question about how to put template class objects into an STL container.
My classes:
class DbValueBase {
protected:
virtual void *null() { return NULL; } // Needed to make class polymorphic
};
template <typename T>
class DbValue : public DbValueBase {
public:
DbValue(const T&val) { data = new T(val); }
~DbValue() { if (data) delete data; }
T *data;
const T& dataref() const { return *data; }
friend std::ostream& operator<<(std::ostream& out, const DbValue<T>& val)
{
out << val.dataref();
return out;
}
}
And, the code snippet where the compile error database.cc:530:90: error: cannot bind ‘std::basic_ostream<char>’ lvalue to ‘std::basic_ostream<char>&&’
occurs:
//nb: typedef std::map<std::string,DbValueBase*> DbValueMap;
const CommPoint::DbValueMap& db_values = cp.value_map();
for (auto i = db_values.cbegin() ; i != db_values.cend() ; i++) {
// TODO: Need to implement an ostream operator, and conversion
// operators, for DbValueBase and DbValue<>
// TODO: Figure out how to get a templated output operator to
// work...
// DbValue<std::string> *k = dynamic_cast<DbValue<std::string>*>(i->second);
std::cerr << " Database field " << i->first << " should have value " << *(i->second) << endl;
}
If my output tries to print i->second
, it compiles and runs, and I see the pointer. If I try to output *(i->second)
, I get the compile error. When single-stepping in gdb, it seems to still know that i->second
is of the correct type
(gdb) p i->second
$2 = (DbValueBase *) 0x680900
(gdb) p *(i->second)
warning: RTTI symbol not found for class 'DbValue<std::string>'
$3 = warning: RTTI symbol not found for class 'DbValue<std::string>'
{_vptr.DbValueBase = 0x4377e0 <vtable for DbValue<std::string>+16>}
(gdb) quit
I'm hoping that I'm doing something subtly wrong. But, it's more complicated than I seem to be able to figure it out on my own. Anyone else see what thing(s) I've done wrong or incompletely?
Edit:
@PiotrNycz did give a good solution for my proposed problem below. However, despite currently printing values while doing development, the real need for these DbValue<>
objects is to have them return a value of the correct type which I can then feed to database operation methods. I should've mentioned that in my original question, that printing is of value, but not the end of my goal.
If you want to print object by base pointer - make the ostream operator in base class:
class DbValueBase {
protected:
virtual ~DbValueBase() {}
virtual void print(std::ostream&) const = 0;
friend std::ostream& operator << (std::ostream& os, const DbValueBase & obj)
{
obj.print(os); return os;
}
};
template <typename T>
class DbValue : public DbValueBase {
public:
void print(std::ostream& os) const
{
out << dataref();
}
};
Although the debugger correctly identifies *(i->second)
as being of the type DbValue<std::string>
, that determination is made using information that is only available at runtime.
The compiler only knows that it is working with a DbValueBase&
and has to generate its code on that basis. Therefore, it can't use the operator<<(std::ostream&, const DbValue<T>&)
as that does not accept a DbValueBase
or subclass.
For obtaining the contents of a DbValue<>
object through a DbValueBase&
, you might want to loop into the Visitor design pattern.
Some example code:
class Visitor {
public:
template <typename T>
void useValue(const T& value);
};
class DbValueBase {
public:
virtual void visit(Visitor&) = 0;
};
template <class T>
class DbValue : public DbValueBase {
pblic:
void visit(Visitor& v) {
v.useValue(m_val);
}
private:
T m_val;
};
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