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Entity Framework - Is there a way to automatically eager-load child entities without Include()?

Is there a way to decorate your POCO classes to automatically eager-load child entities without having to use Include() every time you load them?

Say I have a Class Car, with Complex-typed Properties for Wheels, Doors, Engine, Bumper, Windows, Exhaust, etc. And in my app I need to load my car from my DbContext 20 different places with different queries, etc. I don't want to have to specify that I want to include all of the properties every time I want to load my car.

I want to say

List<Car> cars = db.Car                 .Where(x => c.Make == "Ford").ToList();  //NOT .Include(x => x.Wheels).Include(x => x.Doors).Include(x => x.Engine).Include(x => x.Bumper).Include(x => x.Windows)   foreach(Car car in cars) {  //I don't want a null reference here.  String myString = car.**Bumper**.Title; } 

Can I somehow decorate my POCO class or in my OnModelCreating() or set a configuration in EF that will tell it to just load all the parts of my car when I load my car? I want to do this eagerly, so my understanding is that making my navigation properties virtual is out. I know NHibernate supports similar functionality.

Just wondering if I'm missing something. Thanks in advance!

Cheers,

Nathan

I like the solution below, but am wondering if I can nest the calls to the extension methods. For example, say I have a similar situation with Engine where it has many parts I don't want to include everywhere. Can I do something like this? (I've not found a way for this to work yet). This way if later I find out that Engine needs FuelInjectors, I can add it only in the BuildEngine and not have to also add it in BuildCar. Also if I can nest the calls, how can I nest a call to a collection? Like to call BuildWheel() for each of my wheels from within my BuildCar()?

public static IQueryable<Car> BuildCar(this IQueryable<Car> query) {      return query.Include(x => x.Wheels).BuildWheel()                  .Include(x => x.Doors)                  .Include(x => x.Engine).BuildEngine()                  .Include(x => x.Bumper)                  .Include(x => x.Windows); }  public static IQueryable<Engine> BuildEngine(this IQueryable<Engine> query) {      return query.Include(x => x.Pistons)                  .Include(x => x.Cylendars); }  //Or to handle a collection e.g.  public static IQueryable<Wheel> BuildWheel(this IQueryable<Wheel> query) {      return query.Include(x => x.Rim)                  .Include(x => x.Tire); } 

Here is another very similar thread in case it is helpful to anyone else in this situation, but it still doesn't handle being able to make nexted calls to the extension methods.

Entity framework linq query Include() multiple children entities

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Nathan Geffers Avatar asked Jan 24 '13 22:01

Nathan Geffers


People also ask

How can we achieve eager loading in Entity Framework?

Eager loading is the process whereby a query for one type of entity also loads related entities as part of the query. Eager loading is achieved by use of the Include method. For example, the queries below will load blogs and all the posts related to each blog. Include is an extension method in the System.

Which of the following can be used to eager load data from database in Entity Framework?

Eager loading is achieved using the Include() method.

How does Entity Framework implement lazy loading?

Lazy loading means delaying the loading of related data, until you specifically request for it. When using POCO entity types, lazy loading is achieved by creating instances of derived proxy types and then overriding virtual properties to add the loading hook.


2 Answers

No you cannot do that in mapping. Typical workaround is simple extension method:

public static IQueryable<Car> BuildCar(this IQueryable<Car> query) {      return query.Include(x => x.Wheels)                  .Include(x => x.Doors)                  .Include(x => x.Engine)                  .Include(x => x.Bumper)                  .Include(x => x.Windows); } 

Now every time you want to query Car with all relations you will just do:

var query = from car in db.Cars.BuildCar()             where car.Make == "Ford"             select car; 

Edit:

You cannot nest calls that way. Include works on the core entity you are working with - that entity defines shape of the query so after you call Include(x => Wheels) you are still working with IQueryable<Car> and you cannot call extension method for IQueryable<Engine>. You must again start with Car:

public static IQueryable<Car> BuildCarWheels(this IQuerable<Car> query) {     // This also answers how to eager load nested collections      // Btw. only Select is supported - you cannot use Where, OrderBy or anything else     return query.Include(x => x.Wheels.Select(y => y.Rim))                 .Include(x => x.Wheels.Select(y => y.Tire)); } 

and you will use that method this way:

public static IQueryable<Car> BuildCar(this IQueryable<Car> query) {      return query.BuildCarWheels()                  .Include(x => x.Doors)                  .Include(x => x.Engine)                  .Include(x => x.Bumper)                  .Include(x => x.Windows); } 

The usage does not call Include(x => x.Wheels) because it should be added automatically when you request eager loading of its nested entities.

Beware of complex queries produced by such complex eager loading structures. It may result in very poor performance and a lot of duplicate data transferred from the database.

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Ladislav Mrnka Avatar answered Nov 12 '22 14:11

Ladislav Mrnka


Had this same problem and saw the other link which mentioned an Include attribute. My solution assumes that you created an attribute called IncludeAttribute. With the following extension method and utility method:

    public static IQueryable<T> LoadRelated<T>(this IQueryable<T> originalQuery)     {         Func<IQueryable<T>, IQueryable<T>> includeFunc = f => f;         foreach (var prop in typeof(T).GetProperties()             .Where(p => Attribute.IsDefined(p, typeof(IncludeAttribute))))         {             Func<IQueryable<T>, IQueryable<T>> chainedIncludeFunc = f => f.Include(prop.Name);             includeFunc = Compose(includeFunc, chainedIncludeFunc);         }         return includeFunc(originalQuery);     }      private static Func<T, T> Compose<T>(Func<T, T> innerFunc, Func<T, T> outerFunc)     {         return arg => outerFunc(innerFunc(arg));     } 
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Lunyx Avatar answered Nov 12 '22 12:11

Lunyx