I have defined a tuple thus: (slot, gameid, bitrate)
and created a list of them called myListOfTuples
. In this list might be tuples containing the same gameid
.
E.g. the list can look like:
[
(1, "Solitaire", 1000 ),
(2, "Diner Dash", 22322 ),
(3, "Solitaire", 0 ),
(4, "Super Mario Kart", 854564 ),
... and so on.
]
From this list, I need to create a dictionary of pairs - ( gameId
, bitrate
), where the bitrate
for that gameId
is the first one that I came across for that particular gameId
in myListOfTuples
.
E.g. From the above example - the dictionary of pairs would contain only one pair with gameId
"Solitaire" : ("Solitaire", 1000 )
because 1000 is the first bitrate found.
NB. I can create a set of unique games with this:
uniqueGames = set( (e[1] for e in myListOfTuples ) )
To convert a tuple to dictionary in Python, use the dict() method. A dictionary object can be constructed using a dict() function. The dict() function takes a tuple of tuples as an argument and returns the dictionary.
One of the built-in methods for dictionaries is the . items() methods, which returns a tuple of tuples of the key value pairs found inside the dictionary. We can use this method and pass it into the list() function, in order to generate a list of tuples that contain the key value pairs from our dictionary.
1) Looping all key-value pairs in a dictionary Python dictionary provides a method called items() that returns an object which contains a list of key-value pairs as tuples in a list.
For python2.6
dict(x[1:] for x in reversed(myListOfTuples))
If you have Python2.7 or 3.1, you can use katrielalex's answer
{ gameId: bitrate for _, gameId, bitrate in reversed( myListOfTuples ) }.items( )
(This is a view, not a set. It has setlike operations, but if you need a set, cast it to one.)
Are you sure you want a set, not a dictionary of gameId: bitrate
? The latter seems to me to be a more natural data structure for this problem.
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