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echo'd PHP encode JSON called via AJAX returns what exactly?

I think I'm missing something here:

Using AjAX I get some data from a database and send it back in JSON format $jsondata = array();

while ($Row = mysql_fetch_array($params))
{

    $jsondata[]= array('cat_id'=>$Row["cat_id"], 
                          'category'=>$Row["category"], 
                     'category_desc'=>$Row["category_desc"],
                     'cat_bgd_col'=>$Row["cat_bgd_col"]);
};

echo("{\"Categories\": ".json_encode($jsondata)."};");

No problem so far I think.

On the cleint side I receive back the above into

ajaxRequest.responseText

and if I do this

var categoriesObject = ajaxRequest.responseText; 
alert(categoriesObject);

I see what I expect to see ie the entire array in the alert.

Where it all goes wrong is trying to access the response. The error I get is that the "categoriesObject" is not an object - if not what is it? what's bugginh me is that I can't even access it like this:

document.write(categoriesObject.Categories[0].category);

so what am I doing wrong?

like image 405
T9b Avatar asked Jan 30 '11 22:01

T9b


2 Answers

  1. You should not create JSON manually. Use:

    echo json_encode(array('Categories' => $jsondata));
    

    or just

    echo json_encode($jsondata);
    

    I don't see a reason to add Categories.

  2. You have to decode the JSON on the client side, using JSON.parse (available in most browsers, but also available as script):

    var data = JSON.parse(ajaxRequest.responseText);
    
  3. If you want to be very correct, add

    header('Content-type: application/json');
    

    to your PHP script.

like image 118
Felix Kling Avatar answered Nov 02 '22 21:11

Felix Kling


Are you acutally parsing the JSON? It won't work without.

var categoriesObject = JSON.parse(ajaxRequest.responseText);
like image 31
svens Avatar answered Nov 02 '22 19:11

svens