I use realloc to resize the memory allocated:
char **get_channel_name(void)
{
char **result;
int n;
result = (char **) 0;
for (elem = snd_mixer_first_elem(handle), n = 0; elem; elem = snd_mixer_elem_next(elem)) {
if (!snd_mixer_selem_is_active(elem))
continue;
if (snd_mixer_selem_has_playback_volume(elem) &&
snd_mixer_selem_has_playback_switch(elem) &&
snd_mixer_selem_has_capture_switch(elem)) {
if (result == (char **) 0)
result = (char **) malloc(sizeof(char *));
else
result = (char **) realloc(result, sizeof(char *) * (n + 1)); /* nulled but not freed upon failure */
result[n++] = strdup(snd_mixer_selem_get_name(elem));
}
}
if (result == (char **) 0)
return NULL;
result = (char **) realloc(result, sizeof(char *) * (n + 1)); /* nulled but not freed upon failure */
result[n] = NULL;
return result;
}
When I check code with cppcheck tool static C/C++ code analysis, printed the following warings:
Common realloc mistake: 'result' nulled but not freed upon failure
How can I fix these 2 possible memory leaks?
Description: The realloc() function allocates, reallocates, or frees the block of memory specified by old_blk based on the following rules: If old_blk is NULL, a new block of memory of size bytes is allocated. If the size is zero, the free() function is called to release the memory pointed to by old_blk.
Once you call realloc() , you do not have to free() the memory addressed by pointer passed to realloc() - you have to free() the memory addressed by the pointer realloc() returns. (Unless realloc() returns NULL , in which case the original block of memory - passed to realloc() - has to be free() 'd.)
No, the data will be copied for you into the new block that the returned p points at, before the old block is freed. This all happens before realloc returns, so the new p points to your data still.
The realloc() function changes the size of the memory block pointed to by ptr to size bytes. The contents will be unchanged in the range from the start of the region up to the minimum of the old and new sizes. If the new size is larger than the old size, the added memory will not be initialized.
If realloc()
fails it returns NULL
.
So if you do (and assuming realloc()
would fail)
result = realloc(result, ...);
result
will be assigned NULL
and what it pointed to is not free()
ed and the address to be free()
ed is lost.
To fix this do:
{
void * tmp = realloc(result, ...);
if (NULL == tmp)
{
/* Handle error case, propably freeing what result is pointing to. */
}
else
{
result = tmp;
}
}
The trick to fixing the "nulled but not freed upon failure" error is to store the value returned by realloc
into a separate pointer, and check it for NULL
before reassigning the old pointer:
char **tmp = (char **) realloc(result, sizeof(char *) * (n + 1));
if (tmp) {
result = tmp;
} else {
... // Handle reallocation error
}
Now that the assignment of result
is protected by NULL
check, you have the old value to work with: you could free
it if you want, or you could continue using it if you need to. The original code, on the other hand, does not give you the same option.
Note: When you pass NULL
pointer to realloc
, it behaves like malloc
. That's why you can drop the conditional in the first use of realloc
- replace this
if (result == (char **) 0)
result = (char **) malloc(sizeof(char *));
else
result = (char **) realloc(result, sizeof(char *) * (n + 1));
with this:
char** tmep = (char **) realloc(result, sizeof(char *) * (n + 1));
... // check temp and assign result here
Don't forget to set n
to zero - currently, it's used uninitialized, which is undefined behavior.
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