Now that I`ve downloaded all the messages, and store them to
Message[] temp;
How do I get the list of attachments for each of those messages to
List<File> attachments;
Note: no thirdparty libs, please, just JavaMail.
MimeMessage uses the InternetHeaders class to parse and store the top level RFC 822 headers of a message. The mail. mime. address. strict session property controls the parsing of address headers.
The JavaMail API provides a platform-independent and protocol-independent framework to build mail and messaging applications. The JavaMail API is available as an optional package for use with the Java SE platform and is also included in the Java EE platform.
setText(body); multipart. addBodyPart(msgBodyPart); msgBodyPart = new MimeBodyPart(); //attach file DataSource source = new FileDataSource(attachFile); messageBodyPart. setDataHandler(new DataHandler(source)); messageBodyPart. setFileName(attachFile); multipart.
Without exception handling, but here goes:
List<File> attachments = new ArrayList<File>(); for (Message message : temp) { Multipart multipart = (Multipart) message.getContent(); for (int i = 0; i < multipart.getCount(); i++) { BodyPart bodyPart = multipart.getBodyPart(i); if(!Part.ATTACHMENT.equalsIgnoreCase(bodyPart.getDisposition()) && StringUtils.isBlank(bodyPart.getFileName())) { continue; // dealing with attachments only } InputStream is = bodyPart.getInputStream(); // -- EDIT -- SECURITY ISSUE -- // do not do this in production code -- a malicious email can easily contain this filename: "../etc/passwd", or any other path: They can overwrite _ANY_ file on the system that this code has write access to! // File f = new File("/tmp/" + bodyPart.getFileName()); FileOutputStream fos = new FileOutputStream(f); byte[] buf = new byte[4096]; int bytesRead; while((bytesRead = is.read(buf))!=-1) { fos.write(buf, 0, bytesRead); } fos.close(); attachments.add(f); } }
Question is very old, but maybe it will help someone. I would like to expand David Rabinowitz`s answer.
if(!Part.ATTACHMENT.equalsIgnoreCase(bodyPart.getDisposition()))
should not return all atachments as you expect, because you can have mail where mixed part is without defined disposition.
----boundary_328630_1e15ac03-e817-4763-af99-d4b23cfdb600 Content-Type: application/octet-stream; name="00000000009661222736_236225959_20130731-7.txt" Content-Transfer-Encoding: base64
so in this case, you can also check for filename. Like this:
if (!Part.ATTACHMENT.equalsIgnoreCase(part.getDisposition()) && StringUtils.isBlank(part.getFileName())) {...}
EDIT
there is whole working code using condition descibed above.. Because each part can encapsulate another parts and attachment should be nested in, recursion is used to traverse through all parts
public List<InputStream> getAttachments(Message message) throws Exception { Object content = message.getContent(); if (content instanceof String) return null; if (content instanceof Multipart) { Multipart multipart = (Multipart) content; List<InputStream> result = new ArrayList<InputStream>(); for (int i = 0; i < multipart.getCount(); i++) { result.addAll(getAttachments(multipart.getBodyPart(i))); } return result; } return null; } private List<InputStream> getAttachments(BodyPart part) throws Exception { List<InputStream> result = new ArrayList<InputStream>(); Object content = part.getContent(); if (content instanceof InputStream || content instanceof String) { if (Part.ATTACHMENT.equalsIgnoreCase(part.getDisposition()) || StringUtils.isNotBlank(part.getFileName())) { result.add(part.getInputStream()); return result; } else { return new ArrayList<InputStream>(); } } if (content instanceof Multipart) { Multipart multipart = (Multipart) content; for (int i = 0; i < multipart.getCount(); i++) { BodyPart bodyPart = multipart.getBodyPart(i); result.addAll(getAttachments(bodyPart)); } } return result; }
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