"Integer number too large" error message for 600851475143

Question

public class Three {     public static void main(String[] args) {         Three obj = new Three();         obj.function(600851475143);     }      private Long function(long  i) {         Stack<Long> stack = new Stack<Long>();          for (long j = 2; j <= i; j++) {             if (i % j == 0) {                 stack.push(j);             }         }         return stack.pop();     } } 

When the code above is run, it produces an error on the line obj.function(600851475143);. Why?

Answer 1

600851475143 cannot be represented as a 32-bit integer (type int). It can be represented as a 64-bit integer (type long). long literals in Java end with an "L": 600851475143L