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I would like to download a zip file from internet and extract it.
I would rather use requests. I don't want to write to the disk.
I knew how to do that in Python2 but I am clueless for python3.3. Apparently, zipfile.Zipfile wants a file-like object but I don't know how to get that from what requests returns.
If you know how to do it with urllib.request, I would be curious to see how you do it too.
299
If you just want to save the file from the url you can do: urllib. request. urlretrieve(url, filename) .
Python3. # into a specific location. Import the zipfile module Create a zip file object using ZipFile class. Call the extract() method on the zip file object and pass the name of the file to be extracted and the path where the file needed to be extracted and Extracting the specific file present in the zip.
Unzipping a file with Python is straightforward, We can open the archive using the context manager as we did when creating the zip file, then call the ZipFile. extractall() function and specify a path. That's all there is to it.
Select the . zip file. A pop up appears showing the content of that file. Tap Extract.
I found out how to do it:
request = requests.get(url)
file = zipfile.ZipFile(BytesIO(request.content))
What I was missing :
request.content should be used to access the bytesio.BytesIO is the correct file-like object for bytes.
80
Here's another approach saving you having to install requests:
r = urllib.request.urlopen(req)
with zipfile.ZipFile(BytesIO(r.read())) as z:
print( z.namelist() )
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