Django template tag to display Django version

Question

What is the simplest way to create a Django template tag which displays the Django version on a template?

I want to put the following in a Django template and have it output the Django version (in my case, base.html):

{{ django_version }}

I know that the following Python code outputs the Django version in a shell, but am confused about where I should put this code and how I should call it from the template:

import django
print django.VERSION

UPDATE: I have tried the following in views.py, but nothing shows up in the template:

import django    
from django.template import loader, Context
from django.http import HttpResponse
from django.shortcuts import render_to_response

    def base(request):
        django_version = django.VERSION
        return render_to_response('base.html', {'django_version': django_version} )

Answer 1

Figured this out (currently using Django 1.3) — I needed to append the function name 'django_version' to the TEMPLATE_CONTEXT_PROCESSORS tuple in settings.py:

TEMPLATE_CONTEXT_PROCESSORS = (  
    # ...  
    'myproject.context_processors.django_version',  
)

context_processors.py (thanks to zsquare):

import django
def django_version(request):
    return { 'django_version': django.VERSION }

urls.py:

urlpatterns += patterns('django.views.generic.simple',
    (r'^$', 'direct_to_template', {'template': 'base.html'}),
)

Put the following in your templates, such as base.html:

{{ django_version }}

Answer 2

You may want to use django.get_version() to get the django version in string, the django.VERSION returns a tuple.

>>> import django
>>> django.VERSION
(1, 11, 12, u'final', 0)
>>> django.get_version()
'1.11.12'