The normal way to start the Django server is to run the following command from a terminal or a bash script:
python manage.py runserver [Ip.addr]:[port]
e.g.
python manage.py runserver 0.0.0.0:8000
How can I start a Django server from a Python script?
One option is the following
import os
if __name__ == "__main__":
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "server.settings")
from django.core.management import execute_from_command_line
args = ['name', 'runserver', '0.0.0.0:8000']
execute_from_command_line(args)
Is there a better way?
The runserver command is a built-in subcommand of Django's manage.py file that will start up a development server for this specific Django project.
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Python has already builtin HTTP server
python -m SimpleHTTPServer
OR you have an alternative to run the django server
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "server.settings")
from django.core.management import call_command
from django.core.wsgi import get_wsgi_application
application = get_wsgi_application()
call_command('runserver', '127.0.0.1:8000')
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