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How can I get grep to display the filename before the matching lines in its output?
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ls - displays file names. ls –l - displays file names with permissions, site, owner, etc. man commandname - on-line help for the command specified (Use for complete description).
If you are using GNU grep, then you can use the following: grep -ir --include "*. cpp" "xyz" . The command above says to search recursively starting in current directory ignoring case on the pattern and to only search in files that match the glob pattern "*.
For BSD or GNU grep you can use -B num to set how many lines before the match and -A num for the number of lines after the match. If you want the same number of lines before and after you can use -C num . This will show 3 lines before and 3 lines after.
Try this little trick to coax grep into thinking it is dealing with multiple files, so that it displays the filename:
grep 'pattern' file /dev/null To also get the line number:
grep -n 'pattern' file /dev/null If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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