By the full type of a variable I mean the sort of information that you get in the immediate window:
I would like to determine the type information dynamically using VBA. The function TypeName()
doesn't do what I want since it returns the subtype of a variant and doesn't distinguish between e.g. a variant variable holding a range, an object variable holding a range, and a range variable holding a range.
As a preliminary step, I wrote a function which detects if a variant is passed to it. It works by exploiting pass-by-reference semantics. The code does things with its argument that can only be done with a variant and will thus trigger an error if the passed variable isn't actually a variant:
Function IsVariant(var As Variant) As Boolean Dim temp As Variant Dim isVar As Boolean If IsObject(var) Then Set temp = var Else temp = var End If On Error Resume Next Set var = New Collection var = "test" If Err.Number > 0 Then isVar = False Else isVar = True End If On Error GoTo 0 If IsObject(temp) Then Set var = temp Else var = temp End If IsVariant = isVar End Function
Based on this, I wrote:
Function FullType(var As Variant) As String If IsVariant(var) Then FullType = "Variant/" & TypeName(var) Else FullType = TypeName(var) End If End Function
Testing code:
Sub TestTypes() Dim R As Range Dim Ob As Object Dim i As Integer Dim v1 As Variant Dim v2 As Variant v1 = 10 i = 10 Set v2 = Range("A1") Set Ob = Range("A2") Set R = Range("A3") Debug.Print "v1: " & FullType(v1) Debug.Print "i: " & FullType(i) Debug.Print "v2: " & FullType(v2) Debug.Print "Ob: " & FullType(Ob) Debug.Print "R: " & FullType(R) End Sub
Output:
v1: Variant/Integer i: Integer v2: Variant/Range Ob: Range R: Range
This is almost what I want -- but doesn't distinguish between an object variable holding a range and a range variable holding a range. I've tried to write a function called IsTypeObject
which works similarly to IsVariant
but can't seem to get it to work:
Function IsTypeObject(var As Variant) As Boolean Dim temp As Variant Dim isGeneric As Boolean If (Not IsObject(var)) Or IsVariant(var) Then IsTypeObject = False Exit Function End If Set temp = var On Error Resume Next Set var = New Collection Set var = ActiveWorkbook If Err.Number > 0 Then isGeneric = False Else isGeneric = True End If On Error GoTo 0 Set var = temp IsTypeObject = isGeneric End Function
Test:
Sub test() Dim R As Range Set R = Range("A1") Debug.Print IsTypeObject(R) End Sub
But this prints True
even though I would think that the same pass-by-reference semantics which makes IsVariant
work should also make IsTypeObject
work (you can't assign a collection to a range). I've tried various tweaks but can't seem to distinguish between the generic object variables and specific object variables such as range variables.
So -- any ideas for how to dynamically get the full type of a variable? (The motivation is as part of a debug-log utility)
To check the type of a variable, you can use the type() function, which takes the variable as an input. Inside this function, you have to pass either the variable name or the value itself. And it will return the variable data type.
A variable's data type determines the values that the variable can contain and the operations that can be performed on it. For example, values it can contain. operations which can be performed on it. Integer.
To print the type of variable in Python, use the type() function and to print the variable, use the print() function. The type() is a built-in Python function that returns the variable's data type.
"Data Type" describes the syntax of the data format, how the data is encoded, for example, and transferred via the line as "Value" of a "Variable". "Variable Type" describes a minimum group of components of a complex "Variable" that is shown in the address space.
Yes, you can do this: it requires a little knowledge of pointers and the concept of 'dereferencing'...
Here's the code to do it:
Public Function VariantTypeName(ByRef MyVariant) As String ' Returns the expanded type name of a variable, indicating ' whether it's a simple data type (eg: Long Integer), or a ' Variant containing data of that type, eg: "Variant/Long"
Dim iType As Integer Const VT_BYREF = &H4000&
CopyMemory iType, MyVariant, 2
' iType now contains the VarType of the incoming parameter ' combined with a bitwise VT_BYREF flag indicating that it ' was passed by reference. In other words, it's a pointer, ' not the data structure of the variable (or a copy of it)
' So we should have VT_BYREF - and we'd always expect to ' when MyVariant is a Variant, as variants are a structure ' which uses a pointer (or pointers) to the stored data...
' However, the VBA implementation of a variant will always ' dereference the pointer - all the pointers - passing us ' straight to the data, stripping out all that information ' about references...
If (iType And VT_BYREF) = VT_BYREF Then ' Bitwise arithmetic detects the VT_BYREF flag: VariantTypeName = TypeName(MyVariant) Else ' No VT_BYREF flag. This is a Variant, not a variable: VariantTypeName = "Variant/" & TypeName(MyVariant) End If
End Function
(Declarations for the CopyMemory
API function are a few paragraphs further down).
That needs some explanation, because the Visual Basic family of languages are designed to shield you from the implementation details of variables and their types - and from the concept of pointers in particular - and my code does involve a bit of lateral thinking.
In simple terms, your variables have a name - a string like 'intX' you see in your code; an area of memory allocated to contain the actual data; and an address for that memory.
That address will actually be for the start of the memory allocated to the variable, and the variable will be implemented as a structure in memory defined by offsets to the actual data, with the size (or length) of data - and, for complex types, by offsets to addresses to other structures in memory. Those sizes and offsets are predefined: they are the actual implementation of the variable, and we VBA developers rarely need to know about that - we declare the type, and its all done for us.
The first thing that you need to know today is that the first two bytes at address of a variable in VBA are the enumerated var type: that's how the VarType() Function works.
When the program passes that address, instead of passing a copied allocation of the data in memory, it passes that address as a pointer. Yes, I'm oversimplifying some of this, but VBA developers do actually know the difference between getting a pointer and a copy of the data: it's in the ByRef
and ByVal
identifiers we use for incoming parameters when we declare a function.
VBA and VB are very, very good at shielding us from the details: so good, that we can't use VarType
and TypeName
to detect that we've been passed a value, or a reference to it; or even a reference to a reference, to a reference.
This matters, because a variant is a wrapper for other variables, and the structure gives you a pointer to the variable that it contains with the var type to describe it: however, we have no way of knowing that in VBA - we are passed straight down the line indicated by the address, all the way to the data we are going to use, and the VBA varType
never tells us that we went there indirectly by several hops through successive addresses defined by pointers.
However, that information does exist, if you're prepared to look at those two bytes behind the pointer using an API call.
As I said, those two bytes contain the var type - but there's more: they contain the var type combined with a bitwise marker VT_BYREF
indicating that this is a reference, or pointer, to the stored data type, and not the data itself. So this code will reliably tell you your var type, with a little lateral thinking to get over VBA being helpful when we'd rather it wasn't:
Public Function DereferencedType(ByRef MyVar) As Long
Dim iType As Integer
Const VT_BYREF = &H4000&
' The first two bytes of a variable are the type ID with a ' bitwise OR to VT_BYREF if we were passed the variable by ' reference... Which is exactly what this function does:
CopyMemory iType, MyVar, 2
DereferencedType = iType ' Mod VT_BYREF
'Use "Mod VT_BYREF" to separate out the type if you want
End Function
At a first glance, this function appears to be self-defeating: I'm passing the variable - variant or simple type - by reference, so it's always going to be combined with VT_BYREF
. And I've commented-out the 'modulo' arithmetic anyway... ...And that's how it actually works: pass it a simple variable, and it'll tell you that you passed the variable by reference:
Dim str1 As String str1 = "One Hundred" Debug.Print "String Variable: " & DereferencedType(str1)
...And you get the output vbString OR VT_BYREF
: String Variable: 16392
But if you pass our function a string variant, VBA's implementation of the Variant will shield you from all that complexity about pointers and passing by reference - all the way down to the data - and give you your data with all that unwanted information stripped out:
Dim varX As Variant varX = "One Hundred" Debug.Print "String Variant: " & DereferencedType(varX)
...And you get the output: String Variant: 8
I'll leave you to code up an OR or NOT operation on the returned values with VT_BYREF
, to give you the 'Variant/' label for your expanded string descriptors of the Variant/String and Variant/Long outputs.
[Edit: did that, it's at the top of the answer, implemented as VariantTypeName
]
I recommend that you declare the CopyMemory API call as shown, with conditional compiler constants for all the environments you're likely to encounter:
#If VBA7 And Win64 Then ' 64 bit Excel under 64-bit Windows ' Use LongLong and LongPtr
Private Declare PtrSafe Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" _ (Destination As Any, _ Source As Any, _ ByVal Length As LongLong)
#ElseIf VBA7 Then ' 64 bit Excel in all environments ' Use LongPtr only, LongLong is not available
Private Declare PtrSafe Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" _ (Destination As Any, _ Source As Any, _ ByVal Length As Long)
#Else ' 32 bit Excel
Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" _ (Destination As Any, _ Source As Any, _ ByVal Length As Long) #End If
Meanwhile, the harder question - getting Variant/Object/Range - will need further work. I can tell you that your variant contains a range, and I can tell that it's a variant and not itself a range: but I can't go down the chain of declarations to reveal that an object was declared as 'object' now that it points to a range:
VarX is set equal to a range object variable: varX: type=8204 Range Dereferenced Type=9 rng1: type=8204 Range Dereferenced Type=16393
VarX is set equal to a range object's value, a 2-dimensional array: varX: type=8204 Variant() Dereferenced Type=8204 arr1: type=8204 Variant() Dereferenced Type=8204
The array variable is erased to Empty(). Inspect varX: varX: type=8204 Variant() Dereferenced Type=8204 arr1: type=8204 Variant() Dereferenced Type=8204
VarX is set equal to an 'object' variable, which has been set to a range: varX: type=8204 Range Dereferenced Type=9 obj1: type=8204 Range Dereferenced Type=16393
Here's the code that generated that, and the full output:
Public Sub TestVar()
Dim varX As Variant Dim str1 As String Dim lng1 As Long Dim rng1 As Excel.Range Dim arr1 As Variant Dim obj1 As Object
Debug.Print "Uninitialised:" Debug.Print Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "str1: type=" & VarType(str1) & vbTab & vbTab & TypeName(str1) & vbTab & "Dereferenced Type=" & DereferencedType(str1) Debug.Print vbTab & "lng1: type=" & VarType(lng1) & vbTab & vbTab & TypeName(lng1) & vbTab & "Dereferenced Type=" & DereferencedType(lng1) Debug.Print
varX = "One Hundred" str1 = "One Hundred" lng1 = 100 Debug.Print "varX and str1 are populated with the same literal:" Debug.Print Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "str1: type=" & VarType(str1) & vbTab & vbTab & TypeName(str1) & vbTab & "Dereferenced Type=" & DereferencedType(str1) Debug.Print vbTab & "lng1: type=" & VarType(lng1) & vbTab & vbTab & TypeName(lng1) & vbTab & "Dereferenced Type=" & DereferencedType(lng1) Debug.Print
varX = 100 lng1 = 100 Debug.Print "varX and lng1 are populated with the same integer:" Debug.Print Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "str1: type=" & VarType(str1) & vbTab & vbTab & TypeName(str1) & vbTab & "Dereferenced Type=" & DereferencedType(str1) Debug.Print vbTab & "lng1: type=" & VarType(lng1) & vbTab & vbTab & TypeName(lng1) & vbTab & "Dereferenced Type=" & DereferencedType(lng1) Debug.Print
varX = str1 Debug.Print "VarX is set equal to str1:" Debug.Print Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "str1: type=" & VarType(str1) & vbTab & vbTab & TypeName(str1) & vbTab & "Dereferenced Type=" & DereferencedType(str1) Debug.Print
varX = lng1 Debug.Print "VarX is set equal to lng1:" Debug.Print Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "lng1: type=" & VarType(lng1) & vbTab & vbTab & TypeName(lng1) & vbTab & "Dereferenced Type=" & DereferencedType(lng1) Debug.Print
Set varX = ActiveSheet.Range("A1:C3") Debug.Print "VarX is set equal to a range:" Debug.Print Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print
Set rng1 = ActiveSheet.Range("A1:C3") Set varX = Nothing Set varX = rng1 Debug.Print "VarX is set equal to a range object variable:" Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "rng1: type=" & VarType(rng1) & vbTab & vbTab & TypeName(rng1) & vbTab & "Dereferenced Type=" & DereferencedType(rng1) Debug.Print
arr1 = rng1.Value2 Set varX = Nothing varX = arr1 Debug.Print "VarX is set equal to a range object's value, a 2-dimensional array:" Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "arr1: type=" & VarType(rng1) & vbTab & vbTab & TypeName(arr1) & vbTab & "Dereferenced Type=" & DereferencedType(arr1) Debug.Print
Erase arr1 Debug.Print "The array variable is erased to Empty(). Inspect varX:" Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "arr1: type=" & VarType(rng1) & vbTab & vbTab & TypeName(arr1) & vbTab & "Dereferenced Type=" & DereferencedType(arr1) Debug.Print
Set obj1 = ActiveSheet.Range("A1:C3") Set varX = Nothing Set varX = obj1 Debug.Print "VarX is set equal to an 'object' variable, which has been set to a range:" Debug.Print vbTab & "varX: type=" & VarType(varX) & vbTab & vbTab & TypeName(varX) & vbTab & "Dereferenced Type=" & DereferencedType(varX) Debug.Print vbTab & "obj1: type=" & VarType(rng1) & vbTab & vbTab & TypeName(obj1) & vbTab & "Dereferenced Type=" & DereferencedType(obj1) Debug.Print
End Sub
Results:
Uninitialised: varX: type=0 Empty Dereferenced Type=0 str1: type=8 String Dereferenced Type=16392 lng1: type=3 Long Dereferenced Type=16387
varX and str1 are populated with the same literal: varX: type=8 String Dereferenced Type=8 str1: type=8 String Dereferenced Type=16392 lng1: type=3 Long Dereferenced Type=16387
varX and lng1 are populated with the same integer: varX: type=2 Integer Dereferenced Type=2 str1: type=8 String Dereferenced Type=16392 lng1: type=3 Long Dereferenced Type=16387
VarX is set equal to str1: varX: type=8 String Dereferenced Type=8 str1: type=8 String Dereferenced Type=16392
VarX is set equal to lng1: varX: type=3 Long Dereferenced Type=3 lng1: type=3 Long Dereferenced Type=16387
VarX is set equal to a range: varX: type=8204 Range Dereferenced Type=9
VarX is set equal to a range object variable: varX: type=8204 Range Dereferenced Type=9 rng1: type=8204 Range Dereferenced Type=16393
VarX is set equal to a range object's value, a 2-dimensional array: varX: type=8204 Variant() Dereferenced Type=8204 arr1: type=8204 Variant() Dereferenced Type=8204
The array variable is erased to Empty(). Inspect varX: varX: type=8204 Variant() Dereferenced Type=8204 arr1: type=8204 Variant() Dereferenced Type=8204
VarX is set equal to an 'object' variable, which has been set to a range: varX: type=8204 Range Dereferenced Type=9 obj1: type=8204 Range Dereferenced Type=16393
All in all, an interesting question: the short version of my answer is that you can disambiguate variants and simple types, but an an object declared as 'object' isn't amenable to that analysis.
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