How do I convert a byte array to a string (base 256) in Delphi?
Use the built-in SetString
command. It sets the string to the required length and copies the bytes. There's no need for the array to be null-terminated. In fact, if the array has zero--valued bytes in it, they'll correctly appear within the string; they won't terminate the string.
SetString(AnsiStr, PAnsiChar(@ByteArray[0]), LengthOfByteArray);
If you have a UnicodeString
, then you'll need to halve the length parameter since it measures characters, not bytes:
SetString(UnicodeStr, PWideChar(@ByteArray[0]), LengthOfByteArray div 2);
See also, Converting TMemoryStream to String in Delphi 2009.
I'm not sure what do you mean by Base256. If you want to get hex representation of data, use this:
function bintostr(const bin: array of byte): string;
const HexSymbols = '0123456789ABCDEF';
var i: integer;
begin
SetLength(Result, 2*Length(bin));
for i := 0 to Length(bin)-1 do begin
Result[1 + 2*i + 0] := HexSymbols[1 + bin[i] shr 4];
Result[1 + 2*i + 1] := HexSymbols[1 + bin[i] and $0F];
end;
end;
If you want to just render the data as a string (this doesn't change the content!), where for each byte of data you'd get a single ASCII symbol with that code, do
function bintoAscii(const bin: array of byte): AnsiString;
var i: integer;
begin
SetLength(Result, Length(bin));
for i := 0 to Length(bin)-1 do
Result[1+i] := AnsiChar(bin[i]);
end;
var
LString : string;
LBytes : TArray<byte>;
begin
LBytes := TArray<byte>.Create($01, $02, $03);
LString := TEncoding.ANSI.GetString(ABytes);
end;
Being GetString() the reverse operation of GetBytes().
I think there is another nice way to convert byte arrays in strings - an Indy function called BytesToString
contained in IdGlobal
. It also allows you to specify StartIndex
, Length
and TEncoding
for your string. I've used it several times and I find it very useful.
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