Creating a vector of zeros for a specific size

Question

I'd like to initialize a vector of zeros with a specific size that is determined at runtime.

In C, it would be like:

int main(void) {     uint size = get_uchar();     int A[size][size];     memset(A, 0, size*size*sizeof(int)); } 

Here's the helper function that I tried writing in Rust, but I think the slicing syntax 0..size is offending the compiler. Besides, it looks more verbose than the C version. Is there a more idiomatic way to do this?

fn zeros(size: u32) -> Vec<i32> {     let mut zero_vec: Vec<i32> = Vec::with_capacity(size);     for i in 0..size {         zero_vec.push(0);     }     return zero_vec; } 

I swear that the old docs used to explain a from_elem() method here and none of the permutations of the [0 ; size] notation seem to work

I'd like to stick this into a substring search algorithm ultimately:

pub fn kmp(text: &str, pattern: &str) -> i64 {     let mut shifts = zeros(pattern.len()+1); } 

Answer 1

To initialize a vector of zeros (or any other constant value) of a given length, you can use the vec! macro:

let len = 10; let zero_vec = vec![0; len]; 

That said, your function worked for me after just a couple syntax fixes:

fn zeros(size: u32) -> Vec<i32> {     let mut zero_vec: Vec<i32> = Vec::with_capacity(size as usize);     for i in 0..size {         zero_vec.push(0);     }     return zero_vec; } 

uint no longer exists in Rust 1.0, size needed to be cast as usize, and the types for the vectors needed to match (changed let mut zero_vec: Vec<i64> to let mut zero_vec: Vec<i32>.