I'm using this method http://www.parashift.com/c++-faq-lite/separate-template-fn-defn-from-decl.html to separate the definition of a C++ template function from its declaration, to avoid cluttering up my header files with code.
The link uses as an example a function with no arguments or return, but suppose I have a function with an argument. The link would suggest the following arrangement:
// File "f.h"
template <typename T> void f(T t);
// File "f.cpp"
#include "f.h"
template <typename T> void f(T t) {
// do something
}
template void f<int>(int t);
// other specializations as needed
However it seems the specialization also works if you omit the type in angle brackets, as I suppose the compiler deduces it from the argument type:
template void f(int t);
But I'm wondering, is it valid to do that?
Visual C++ 12 (2013)
To instantiate a template function explicitly, follow the template keyword by a declaration (not definition) for the function, with the function identifier followed by the template arguments. template float twice<float>( float original ); Template arguments may be omitted when the compiler can infer them.
Class Template Declarationtemplate <class T> class className { private: T var; ... .. ... public: T functionName(T arg); ... .. ... }; In the above declaration, T is the template argument which is a placeholder for the data type used, and class is a keyword.
What is the correct syntax of defining function template/template functions? Explanation: Starts with keyword template and then <class VAR>, then use VAR as type anywhere in the function below.
Templates in c++ is defined as a blueprint or formula for creating a generic class or a function. Generic Programming is an approach to programming where generic types are used as parameters in algorithms to work for a variety of data types.In C++, a template is a straightforward yet effective tool.
Yes, it's valid. [temp.explicit] p3 says:
If the explicit instantiation is for a function or member function, the unqualified- id in the declaration shall be either a template-id or, where all template arguments can be deduced, a template-name or operator-function-id.
Your function has one template parameter and it can be deduced from the function argument, when the function parameter is int
the template argument can be deduced as int
, so you can (optionally) use the template-name, f
, instead of the template-id f<int>
.
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