Converting uneven rows to columns with FasterCSV

Question

I have a CSV data file with rows that may have lots of columns 500+ and some with a lot less. I need to transpose it so that each row becomes a column in the output file. The problem is that the rows in the original file may not all have the same number of columns so when I try the transpose method of array I get:

`transpose': element size differs (12 should be 5) (IndexError)

Is there an alternative to transpose that works with uneven array length?

Answer 1

I would insert nulls to fill the holes in your matrix, something such as:

a = [[1, 2, 3], [3, 4]]

# This would throw the error you're talking about
# a.transpose

# Largest row
size = a.max { |r1, r2| r1.size <=> r2.size }.size

# Enlarge matrix inserting nils as needed
a.each { |r| r[size - 1] ||= nil }

# So now a == [[1, 2, 3], [3, 4, nil]]
aa = a.transpose

# aa == [[1, 3], [2, 4], [3, nil]]