Related to Stack Overflow question Scala equivalent of new HashSet(Collection) , how do I convert a Java collection (java.util.List
say) into a Scala collection List
?
I am actually trying to convert a Java API call to Spring's SimpleJdbcTemplate
, which returns a java.util.List<T>
, into a Scala immutable HashSet
. So for example:
val l: java.util.List[String] = javaApi.query( ... )
val s: HashSet[String] = //make a set from l
This seems to work. Criticism is welcome!
import scala.collection.immutable.Set
import scala.collection.jcl.Buffer
val s: scala.collection.Set[String] =
Set(Buffer(javaApi.query( ... ) ) : _ *)
For future reference: With Scala 2.8, it could be done like this:
import scala.collection.JavaConversions._
val list = new java.util.ArrayList[String]()
list.add("test")
val set = list.toSet
set
is a scala.collection.immutable.Set[String]
after this.
Also see Ben James' answer for a more explicit way (using JavaConverters), which seems to be recommended now.
If you want to be more explicit than the JavaConversions demonstrated in robinst's answer, you can use JavaConverters:
import scala.collection.JavaConverters._
val l = new java.util.ArrayList[java.lang.String]
val s = l.asScala.toSet
JavaConversions (robinst's answer) and JavaConverters (Ben James's answer) have been deprecated with Scala 2.10.
Instead of JavaConversions use:
import scala.collection.convert.wrapAll._
as suggested by aleksandr_hramcov.
Instead of JavaConverters use:
import scala.collection.convert.decorateAll._
For both there is also the possibility to only import the conversions/converters to Java or Scala respectively, e.g.:
import scala.collection.convert.wrapAsScala._
Update: The statement above that JavaConversions and JavaConverters were deprecated seems to be wrong. There were some deprecated properties in Scala 2.10, which resulted in deprecation warnings when importing them. So the alternate imports here seem to be only aliases. Though I still prefer them, as IMHO the names are more appropriate.
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