Convert SVG to PNG in Python

Question

Here is what I did using cairosvg:

from cairosvg import svg2png

svg_code = """
    <svg xmlns="http://www.w3.org/2000/svg" width="24" height="24" viewBox="0 0 24 24" fill="none" stroke="#000" stroke-width="2" stroke-linecap="round" stroke-linejoin="round">
        <circle cx="12" cy="12" r="10"/>
        <line x1="12" y1="8" x2="12" y2="12"/>
        <line x1="12" y1="16" x2="12" y2="16"/>
    </svg>
"""

svg2png(bytestring=svg_code,write_to='output.png')

And it works like a charm!

See more: cairosvg document

The answer is "pyrsvg" - a Python binding for librsvg.

There is an Ubuntu python-rsvg package providing it. Searching Google for its name is poor because its source code seems to be contained inside the "gnome-python-desktop" Gnome project GIT repository.

I made a minimalist "hello world" that renders SVG to a cairo surface and writes it to disk:

import cairo
import rsvg

img = cairo.ImageSurface(cairo.FORMAT_ARGB32, 640,480)

ctx = cairo.Context(img)

## handle = rsvg.Handle(<svg filename>)
# or, for in memory SVG data:
handle= rsvg.Handle(None, str(<svg data>))

handle.render_cairo(ctx)

img.write_to_png("svg.png")

Update: as of 2014 the needed package for Fedora Linux distribution is: gnome-python2-rsvg. The above snippet listing still works as-is.

Install Inkscape and call it as command line:

${INKSCAPE_PATH} -z -f ${source_svg} -w ${width} -j -e ${dest_png}

You can also snap specific rectangular area only using parameter -j, e.g. co-ordinate "0:125:451:217"

${INKSCAPE_PATH} -z -f ${source_svg} -w ${width} -j -a ${coordinates} -e ${dest_png}

If you want to show only one object in the SVG file, you can specify the parameter -i with the object id that you have setup in the SVG. It hides everything else.

${INKSCAPE_PATH} -z -f ${source_svg} -w ${width} -i ${object} -j -a ${coordinates} -e ${dest_png}

I'm using Wand-py (an implementation of the Wand wrapper around ImageMagick) to import some pretty advanced SVGs and so far have seen great results! This is all the code it takes:

    with wand.image.Image( blob=svg_file.read(), format="svg" ) as image:
        png_image = image.make_blob("png")

I just discovered this today, and felt like it was worth sharing for anyone else who might straggle across this answer as it's been a while since most of these questions were answered.

NOTE: Technically in testing I discovered you don't even actually have to pass in the format parameter for ImageMagick, so with wand.image.Image( blob=svg_file.read() ) as image: was all that was really needed.

EDIT: From an attempted edit by qris, here's some helpful code that lets you use ImageMagick with an SVG that has a transparent background:

from wand.api import library
import wand.color
import wand.image

with wand.image.Image() as image:
    with wand.color.Color('transparent') as background_color:
        library.MagickSetBackgroundColor(image.wand, 
                                         background_color.resource) 
    image.read(blob=svg_file.read(), format="svg")
    png_image = image.make_blob("png32")

with open(output_filename, "wb") as out:
    out.write(png_image)

I did not find any of the answers satisfactory. All the mentioned libraries have some problem or the other like Cairo dropping support for python 3.6 (they dropped Python 2 support some 3 years ago!). Also, installing the mentioned libraries on the Mac was a pain.

Finally, I found the best solution was svglib + reportlab. Both installed without a hitch using pip and first call to convert from svg to png worked beautifully! Very happy with the solution.

Just 2 commands do the trick:

from svglib.svglib import svg2rlg
from reportlab.graphics import renderPM
drawing = svg2rlg("my.svg")
renderPM.drawToFile(drawing, "my.png", fmt="PNG")

Are there any limitations with these I should be aware of?