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If I define an enum like so:
enum Foo : bool { Left = false, Right = true };
then try to construct one from a boolean like so:
int main (int ac, const char **av) {
Foo foo ( ac > 1 );
cout << boolalpha << bool(foo) << endl;
return 0;
}
it fails, but works with an extra constructor like so:
Foo foo ( Foo( ac > 1 ) );
Why is this? I thought Foo foo (...) was an explicit constructor call?
312
if you need your enum to contain boolean data in addition to the enum constant's type value, you could add a simple attribute to your enum, taking a boolean value. Then you can add an extension method for your enum that fetches the attribute and returns its boolean value.
Enumeration is a user defined datatype in C/C++ language. It is used to assign names to the integral constants which makes a program easy to read and maintain. The keyword “enum” is used to declare an enumeration. The following is the syntax of enums. enum enum_name{const1, const2, ....... };
I don't think you can do this:
Foo foo ( ac > 1 );
Suppose you define Foo enum as:
enum Foo : bool { Left = false };
What would happen if you called:
Foo foo(true);
You don't have appropriate enum value for what you want to initialize with.
190
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