I am trying to write my own version of IndexingIterator
to increase my understanding of Sequence
. I haven't assign any type to associatetype Iterator in my struct. However, the complier doesn't complain about that and I get a default implementation of makeIterator
.
Following are my codes:
struct __IndexingIterator<Elements: IndexableBase>: Sequence, IteratorProtocol {
mutating func next() -> Elements._Element? {
return nil
}
}
let iterator = __IndexingIterator<[String]>()
// this works and returns an instance of __IndexingIterator<Array<String>>. why?
iterator.makeIterator()
I think there must be some extensions on Sequence
which add the default implementation. Thus, I searched it in Sequence.swift
and only found this.
extension Sequence where Self.Iterator == Self, Self : IteratorProtocol {
/// Returns an iterator over the elements of this sequence.
public func makeIterator() -> Self {
return self
}
}
I thought it would be like this:
extension Sequence where Self: IteratorProtocol {
typealias Iterator = Self
...
}
Did I miss something or I misunderstood the extension?
To add Sequence conformance to your own custom type, add a makeIterator() method that returns an iterator. Alternatively, if your type can act as its own iterator, implementing the requirements of the IteratorProtocol protocol and declaring conformance to both Sequence and IteratorProtocol are sufficient.
Sequences provide access to their elements by creating an iterator, which keeps track of its iteration process and returns one element at a time as it advances through the sequence. Whenever you use a for - in loop with an array, set, or any other collection or sequence, you're using that type's iterator.
Iterators in Python Iterator in Python is simply an object that can be iterated upon. An object which will return data, one element at a time. Technically speaking, a Python iterator object must implement two special methods, __iter__() and __next__() , collectively called the iterator protocol.
It looks like Alexander's answer is correct. Here's a boiled down version, without using Sequence
:
protocol MySequence {
associatedtype Iterator: IteratorProtocol
func maakeIterator() -> Iterator
}
extension MySequence where Self.Iterator == Self, Self : IteratorProtocol {
/// Returns an iterator over the elements of this sequence.
func maakeIterator() -> Self {
return self
}
}
struct __IndexingIterator<Element>: MySequence, IteratorProtocol {
mutating func next() -> Element? {
return nil
}
}
let iterator = __IndexingIterator<[String]>()
iterator.maakeIterator()
You can write your own Iterator which confrom to IteratorProtocol
first, then write what you need confrom to Sequence
.
Make sure that you have to implement requried func.
struct IteratorTest : IteratorProtocol {
typealias Element = Int
var count : Int
init(count :Int) {
self.count = count
}
mutating func next() -> Int? {
if count == 0 {
return nil
}else {
defer {
count -= 1
}
return count;
}
}
}
struct CountDown : Sequence {
typealias Iterator = IteratorTest
func makeIterator() -> IteratorTest {
return IteratorTest.init(count: 10)
}
}
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