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Conditionally load module on the empty path in Angular router

I'm trying to load the home page of my app for visitors who are not authenticated.

const routes: Routes = [
    { path: '', loadChildren: './home/home.module#HomeModule' }
...

Authenticated users should get their feed via that module, also on the empty path.

{ path: '', loadChildren: './feed/feed.module#FeedModule', canActivate: [IsAuthenticationGuard] },
{ path: '', loadChildren: './home/home.module#HomeModule', canActivate: [NoAuthenticationGuard] },

I would expect that IsAuthenticationGuard would fail and load the default home component.

Instead it DOES download the feed module package (shown in the network tab) but loads nothing in the router outlet. Very confusing.

How can I do conditional routing (based on guards or otherwise) on the empty path?

Update: Here are the guards by request

@Injectable()
export class IsAuthenticationGuard implements CanActivate {
    constructor(
        private authenticationService: AuthenticationService
    ) { }

    public canActivate(
        route: ActivatedRouteSnapshot,
        state: RouterStateSnapshot
    ): Observable<boolean> {
        return this.authenticationService.isAuthenticated.pipe(take(1), map((isAuthentication) => {
            return isAuthentication;
        }));
    }
}

I've researched the new urlTree and it's cool that you can now redirect via the route instead of within the guard. However, redirects don't seem applicable if you're trying to use the same route with a different module. Plz correct me if there is a way.

like image 466
Ben Racicot Avatar asked Dec 26 '18 21:12

Ben Racicot


2 Answers

It turns out that this was basically not (safely) possible until Ivy. Now in Angular 9/10 we can lazy load feature-modules without the router very easily.

StackBlitz
V13 StackBlitz Update

@Component({
    selector: 'my-app',
    templateUrl: './app.component.html',
})
export class AppComponent implements OnInit  {
    @ViewChild('container', { read: ViewContainerRef }) container: ViewContainerRef;

    constructor( 
        private compiler: Compiler,
        private injector: Injector
    ){  }

    public ngOnInit(): void {
        if (loggedin) {
            this.loadModule(await import('./lazy/lazy.module').then(m => m.LazyModule));
        } else {
            this.loadModule(await import('./lazy2/lazy2.module').then(m => m.Lazy2Module));
        }
    }

    async loadModule(module: Type<any>) {
        let ref;
        try {
            this.container.clear();

            // Angular < 13 
            const moduleFactory = await this.compiler.compileModuleAsync(module);
            const moduleRef: any = moduleFactory.create(this.injector);
            const componentFactory = moduleRef.instance.resolveComponent(); // ASSERTION ERROR
            ref = this.container.createComponent(componentFactory, null, moduleRef.injector);

            // Angular 13 update
            const moduleRef = createNgModuleRef(module, this.injector);
            const componentFactory = moduleRef.instance.resolveComponent();
            ref = container.createComponent(
                componentFactory,
                undefined,
                moduleRef.injector
            );

        } catch (e) {
            console.error(e);
        }
            return ref;
        }
    }
like image 186
Ben Racicot Avatar answered Sep 29 '22 00:09

Ben Racicot


There are a couple things that you are doing wrong in my opinion.

  1. You shouldn't have two routes defined with the same path.
  2. In your guard the map is pointless. As long as your service method returns Observable<boolean> you don't need to map its value.
  3. Also in your guard if you're not returning true, you need to navigate to the other module's path. For that you will need to implement some other logic for telling whether the user is logged in or not.

Take a look at the official angular routing guide here. There is a lot of useful information that will help you. Especially these:

  • recommended guard implementation
  • debugging routing in your application

EDIT 2018/12/27

So if the question is how to conditionally load two feature modules on the same path,

the answer is, in my experience, you cannot.

like image 24
bodorgergely Avatar answered Sep 29 '22 00:09

bodorgergely