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For example, I had an array with 3 numbers:
var arr = [124, -50, 24];
and I need to convert this array to the object:
{
x: 124,
y: -50,
z: 24
}
I don`t want to use "old-style" syntax for this, for example:
{
x: arr[0],
y: arr[1],
z: arr[2]
}
so for now, I`m using that syntax:
const [x, y, z] = [...arr];
const obj = {x, y, z};
But, is there is any way to do this with a straight dectructuring array to object without need of temporary variables?
213
Destructuring is a JavaScript expression that allows us to extract data from arrays, objects, and maps and set them into new, distinct variables. Destructuring allows us to extract multiple properties, or items, from an array at a time.
In the first line, we are declaring a new variable studentsArr , and assigning it the value of an array of student names. Line 2 is where we destructure. In line 2 we declare three variables; first , second , and third . By declaring them on the left-hand side, we initiate destructuring.
Array destructuring is a unique technique that allows you to neatly extract an array's value into new variables.
As it was already mentioned in the comment you can use an Immediately Invoked Function Expression (IIFE) to create the object in a single step, but it's less readable then multiple steps.
const arr = [124, -50, 24];
const obj = (([x, y, z]) => ({ x, y, z }))(arr);
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