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Conditional formatting of a table in RShiny

I'm trying to visualize a cohort analysis, and wanted to use RenderDataTable in shiny to get this sort of a visualization where I would be able to highlight all the cells based on a separate column having values 1/0, with 1 being shaded and 0 not being shaded.

Cohort Table

I Tried a couple of things, including trying to use geom_tile in ggplot2, but it was of no avail. I also tried looking at rpivotTable, but I wasn't able to figure out how to shade certain cells.

Example Data:

df <- "
cohort  wk  value   flag
1   1   24  0
1   2   12  0
1   3   10  0
1   4   5   0
1   5   2   0
2   1   75  0
2   2   43  1
2   3   11  0
2   4   14  0
3   1   97  0
3   2   35  0
3   3   12  1
4   1   9   0
4   2   4   0
5   1   5   0"

df <- read.table(text = df, header = TRUE)
like image 567
Karthik g Avatar asked Aug 08 '15 01:08

Karthik g


2 Answers

With the DT-package:

# global.R

library(shiny)
library(DT)

sketch = htmltools::withTags(table(
  class = 'display',
    thead(
       tr(
         th(rowspan = 2, ''),
         th(rowspan = 2, 'Cohort'),
         th(colspan = 10, 'Wk')
       ),
       tr(lapply(paste(c('', 'f'), rep(1:5, each=2), sep=''), th))
    )
))

# ui.R

shinyUI( fluidPage( DT::dataTableOutput(outputId="table") ) )

# server.R

shinyServer(function(input, output, session) {
    output$table <- DT::renderDataTable({
        df$flag <- as.factor(df$flag)
        x <-  reshape(df, timevar = 'wk', sep = '_', direction = 'wide',idvar ='cohort')
        row.names(x) <- NULL
        colnames(x)[-1] <- paste(c('', 'f'), rep(1:5, each = 2), sep = '')
        datatable(x, rownames = T, container = sketch,
          options = list(dom = 'C<"clear">rti', pageLength = -1,
                         columnDefs = list(list(visible = F, targets = c(3,5,7,9,11))))
    )%>%
       formatStyle('1', 'f1', backgroundColor = styleEqual(c(0, 1), c('white','lightblue'))) %>%
       formatStyle('2', 'f2', backgroundColor = styleEqual(c(0, 1), c('white','lightblue'))) %>%
       formatStyle('3', 'f3', backgroundColor = styleEqual(c(0, 1), c('white','lightblue'))) %>%
       formatStyle('4', 'f4', backgroundColor = styleEqual(c(0, 1), c('white','lightblue'))) %>%
       formatStyle('5', 'f5', backgroundColor = styleEqual(c(0, 1), c('white','lightblue'))) 
    })  
})  

\

enter image description here

like image 169
user5029763 Avatar answered Oct 13 '22 01:10

user5029763


If you want to color a DataTable you could do it like this:

require(plyr)

# Create matrix
m.val <- max(unlist(lapply(unique(df$cohort),function(ch){ length(which(df$cohort==ch)) })))
cohort.df <-  do.call(rbind, lapply(unique(df$cohort),function(ch){ 
  v <- df$value[which(df$cohort==ch)]
  c(v,rep(NA,m.val-length(v))) 
  }))

ui <- fluidPage(
  tags$head(
    tags$script(
      HTML("
        Shiny.addCustomMessageHandler ('colorTbl',function (message) {
          console.log(message.row);
          var row = parseInt(message.row); var col = parseInt(message.col);
          $('#tbl').find('tbody').find('tr').eq(row).find('td').eq(col).css('background',message.color);
        });
           ")
    )
  ),
  dataTableOutput("tbl")
)

color <- "#6CAEC4"
server <- function(input, output, session) {
  colorTbl <- function(){
    # Get rows we want to color
    sel.d <- df[df$flag==1,]
    for(i in 1:nrow(sel.d)){
      row <- as.numeric(sel.d[i,sel.d$cohort]) -1
      col <- as.numeric(sel.d[i,sel.d$wk]) - 1
      session$sendCustomMessage(type = 'colorTbl', message = list(row=row,col=col,color=color))
    }
  }

  output$tbl <- renderDataTable({
    # Wait until table is rendered, then color
    reactiveTimer(200,{colorTbl()})
    as.data.frame(cohort.df)
  })
}

runApp(shinyApp(ui,server))

Here I use jQuery to color the rows based on your criterion.

like image 20
RmIu Avatar answered Oct 12 '22 23:10

RmIu