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I would like to concatenate all the arguments passed to my bash script except the flag.
So for example, If the script takes inputs as follows:
./myBashScript.sh -flag1 exampleString1 exampleString2
I want the result to be "exampleString1_exampleString2"
I can do this for a predefined number of inputs (i.e. 2), but how can i do it for an arbitrary number of inputs?
224
The += Operator in Bash Bash is a widely used shell in Linux, and it supports the '+=' operator to concatenate two variables. As the example above shows, in Bash, we can easily use the += operator to concatenate string variables.
Assigning the arguments to a regular variable (as in args="$@" ) mashes all the arguments together like "$*" does. If you want to store the arguments in a variable, use an array with args=("$@") (the parentheses make it an array), and then reference them as e.g. "${args[0]}" etc.
4. OR Operator (||) The OR Operator (||) is much like an 'else' statement in programming. The above operator allow you to execute second command only if the execution of first command fails, i.e., the exit status of first command is '1'.
function concatenate_args
{
string=""
for a in "$@" # Loop over arguments
do
if [[ "${a:0:1}" != "-" ]] # Ignore flags (first character is -)
then
if [[ "$string" != "" ]]
then
string+="_" # Delimeter
fi
string+="$a"
fi
done
echo "$string"
}
# Usage:
args="$(concatenate_args "$@")"
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