I request your help in R to resolve the issue. I have dataframes as given below
df1
a,b,c,d
1,2,3,4
1,2,3,4
1,2,3,4
df2
a,b,c,d
1,2,3,4
1,2,3,4
1,2,3,4
1,2,3,4
I need to perform an operation on each dataframe as given below
df1$value <- 0.12*df1$a+0.24*df1$b+0.56*df1$c
As read from another Stack Overflow answer, it is advised to put in a list of all the dataframes. I was trying use the below statement to do so. It worked
df_list <- list(ls(pattern='df*'))
Now I am not able to compute the new attribute with below code using lapply
res <- lapply(dflist, function(x) {
0.12*grep(x[[a]])+0.24*grep(x[[b]])+0.56*grep(x[[c]]))
})
After performing the above operation I want to reform my dataframes without a list.
In R
, it is better keep the data.frames in a list
. If we really need to update the data.frames objects in the global environment, use list2env
after transform
ing the 'df_list' with a 'value' column.
df_list <- mget(ls(pattern='df\\d+'))
res <- lapply(df_list, transform, value = 0.12*a + 0.24*b + 0.56*c)
list2env(res, envir = .GlobalEnv)
df1
# a b c d value
#1 1 2 3 4 2.28
#2 1 2 3 4 2.28
#3 1 2 3 4 2.28
df2
# a b c d value
#1 1 2 3 4 2.28
#2 1 2 3 4 2.28
#3 1 2 3 4 2.28
#4 1 2 3 4 2.28
We get the values of the string (ls(pattern='df\\d+'))
) in a list
using mget
, then loop through the list
of data.frame
s (lapply(df_list, ...
), transform
to create a new column 'value' in each of the data.frame
and finally update the objects in the global environment with list2env
.
df1 <- structure(list(a = c(1L, 1L, 1L), b = c(2L, 2L, 2L), c = c(3L,
3L, 3L), d = c(4L, 4L, 4L)), .Names = c("a", "b", "c", "d"),
class = "data.frame", row.names = c(NA, -3L))
df2 <- structure(list(a = c(1L, 1L, 1L, 1L), b = c(2L, 2L, 2L, 2L),
c = c(3L, 3L, 3L, 3L), d = c(4L, 4L, 4L, 4L)), .Names = c("a",
"b", "c", "d"), row.names = c(NA, -4L), class = "data.frame")
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