This command works fine:
$ bash -s stable < <(curl -s https://raw.github.com/wayneeseguin/rvm/master/binscripts/rvm-installer)
However, I don't understand how exactly stable
is passed as a parameter to the shell script that is downloaded by curl. That's the reason why I fail to achieve the same functionality from within my own shell script - it gives me ./foo.sh: 2: Syntax error: redirection unexpected
:
$ cat foo.sh
#!/bin/sh
bash -s stable < <(curl -s https://raw.github.com/wayneeseguin/rvm/master/binscripts/rvm-installer)
So, the questions are: how exactly this stable
param gets to the script, why are there two redirects in this command, and how do I change this command to make it work inside my script?
That's not related to stable
, it's related to your script using /bin/sh
, not bash
. The <()
syntax is unavailable in POSIX shells, which includes bash when invoked as /bin/sh
(in which case it turns off nonstandard functionality for compatibility reasons).
Make your shebang line #!/bin/bash
.
< <()
idiom:To be clear about what's going on -- <()
is replaced with a filename which refers to the output of the command which it runs; on Linux, this is typically a /dev/fd/##
type filename. Running < <(command)
, then, is taking that file and directing it to your stdin... which is pretty close the behavior of a pipe.
To understand why this idiom is useful, compare this:
read foo < <(echo "bar")
echo "$foo"
to this:
echo "bar" | read foo
echo "$foo"
The former works, because the read is executed by the same shell that later echoes the result. The latter does not, because the read is run in a subshell that was created just to set up the pipeline and then destroyed, so the variable is no longer present for the subsequent echo.
bash -s stable
:bash -s
indicates that the script to run will come in on stdin. All arguments, then, are fed to the script in the $@
array ($1
, $2
, etc), so stable
becomes $1
when the script fed in on stdin is run.
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