I have a vector like this :
vector< vector<int> > myVector;
All row and column numbers are same in this vector.
I want to find row count and column count of this vector.
For row count I come up with :
myVector[0].size();
For column count, I can't come up with anything. Can you tell me if my row count is correct and can you tell me how I can get column count? Thanks.
vector_name. size() gives you the numbers of column in a 2D vector and vector_name[0]. size() gives you the numbers of rows in a 2D vector in C++.
Vectors are geometric objects. A particular vector can be represented in a variety of ways. It is important to understand the difference between a geometric object (such as a point or a vector) and the way it is represented (often with a column matrix).
You have a vector of integer vectors myVector[0].size()
returns you the amount of elements in the first int vector in the 2d vector.
The structure of such vector looks like this:
myVector[ Vector[0, 4, 2, 5], Vector[1, 4, 2] ];
When you call for myVector[1].size() it would return 3 and [0] would return 4.
For the amount of rows (int vectors) in the 2d vector, you can just use myVector.size()
You can run this to see it in actions
#include <iostream> #include <vector> int main(){ std::vector<std::vector<int>>MyVector; std::vector<int>temp; temp.push_back(1); temp.push_back(2); temp.push_back(3); MyVector.push_back(temp); std::cout << "Rows in the 2d vector: " << MyVector.size() << std::endl << "Collumns in the 1st row: " << MyVector[0].size() << std::endl; system("pause"); return 0; }
This is the output:
Rows in the 2d vector: 1 Collumns in the 1st row: 3
for(int i=0;i<v.size();i++){ for(int j=0;j<v[i].size();j++){ cout<<v[i][j]<<" "; } cout<<endl; }
Here v is a two dimensional vector of varying size in terms of column size. Use v.size() as it gives the total number of rows and v[i].size() gives you the total number of colums in ith row. The following code can be used to iterate through varying two dimensional vector.
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