Cast to function pointer

Question

I have come across the line of code shown below.

I think it may be a cast to a function pointer that returns void and takes a void pointer. Is that correct?

(void (*)(void *))SGENT_1_calc 

Answer 1

Yes, it is correct. I find that not very readable, so I suggest declaring the signature of the function to be pointed:

 typedef void sigrout_t(void*); 

^{I also have the coding convention that types ending with rout_t are such types for functions signatures. You might name it otherwise, since _t is a suffix reserved by POSIX.}

Later on I am casting, perhaps to call it like

 ((sigrout_t*) SGENT_1_calc) (someptr);