Get called function name as string

Question

I'd like to display the name of a function I'm calling. Here is my code

void (*tabFtPtr [nbExo])(); // Array of function pointers int i; for (i = 0; i < nbExo; ++i) {     printf ("%d - %s", i, __function__); } 

I used __function__ as an exemple because it's pretty close from what I'd like but I want to display the name of the function pointed by tabFtPtr [nbExo].

Thanks for helping me :)

Answer 1

You need a C compiler that follows the C99 standard or later. There is a pre-defined identifier called __func__ which does what you are asking for.

void func (void) {   printf("%s", __func__); } 

Edit:

As a curious reference, the C standard 6.4.2.2 dictates that the above is exactly the same as if you would have explicitly written:

void func (void) {   static const char f [] = "func"; // where func is the function's name   printf("%s", f); } 

Edit 2:

So for getting the name through a function pointer, you could construct something like this:

const char* func (bool whoami, ...) {   const char* result;    if(whoami)   {     result = __func__;   }   else   {     do_work();     result = NULL;   }    return result; }  int main() {   typedef const char*(*func_t)(bool x, ...);    func_t function [N] = ...; // array of func pointers    for(int i=0; i<N; i++)   {     printf("%s", function[i](true, ...);   } }