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Cast Object to Generic Type for returning

People also ask

Do generics prevent type cast errors?

Implementing generics into your code can greatly improve its overall quality by preventing unprecedented runtime errors involving data types and typecasting.

What is generic type casting in Java?

The Java Generics programming is introduced in J2SE 5 to deal with type-safe objects. It makes the code stable by detecting the bugs at compile time. Before generics, we can store any type of objects in the collection, i.e., non-generic. Now generics force the java programmer to store a specific type of objects.

Can you create an object of generic type?

A generic type is like a template. You cannot create instances of it unless you specify real types for its generic type parameters. To do this at run time, using reflection, requires the MakeGenericType method.

Can you typecast an object in Java?

Type Casting is a feature in Java using which the form or type of a variable or object is cast into some other kind or Object, and the process of conversion from one type to another is called Type Casting.


You have to use a Class instance because of the generic type erasure during compilation.

public static <T> T convertInstanceOfObject(Object o, Class<T> clazz) {
    try {
        return clazz.cast(o);
    } catch(ClassCastException e) {
        return null;
    }
}

The declaration of that method is:

public T cast(Object o)

This can also be used for array types. It would look like this:

final Class<int[]> intArrayType = int[].class;
final Object someObject = new int[]{1,2,3};
final int[] instance = convertInstanceOfObject(someObject, intArrayType);

Note that when someObject is passed to convertToInstanceOfObject it has the compile time type Object.


I stumble upon this question and it grabbed my interest. The accepted answer is completely correct, but I thought I do provide my findings at JVM byte code level to explain why the OP encounter the ClassCastException.

I have the code which is pretty much the same as OP's code:

public static <T> T convertInstanceOfObject(Object o) {
    try {
       return (T) o;
    } catch (ClassCastException e) {
        return null;
    }
}

public static void main(String[] args) {
    String k = convertInstanceOfObject(345435.34);
    System.out.println(k);
}

and the corresponding byte code is:

public static <T> T convertInstanceOfObject(java.lang.Object);
    Code:
       0: aload_0
       1: areturn
       2: astore_1
       3: aconst_null
       4: areturn
    Exception table:
       from    to  target type
           0     1     2   Class java/lang/ClassCastException

  public static void main(java.lang.String[]);
    Code:
       0: ldc2_w        #3                  // double 345435.34d
       3: invokestatic  #5                  // Method java/lang/Double.valueOf:(D)Ljava/lang/Double;
       6: invokestatic  #6                  // Method convertInstanceOfObject:(Ljava/lang/Object;)Ljava/lang/Object;
       9: checkcast     #7                  // class java/lang/String
      12: astore_1
      13: getstatic     #8                  // Field java/lang/System.out:Ljava/io/PrintStream;
      16: aload_1
      17: invokevirtual #9                  // Method java/io/PrintStream.println:(Ljava/lang/String;)V
      20: return

Notice that checkcast byte code instruction happens in the main method not the convertInstanceOfObject and convertInstanceOfObject method does not have any instruction that can throw ClassCastException. Because the main method does not catch the ClassCastException hence when you execute the main method you will get a ClassCastException and not the expectation of printing null.

Now I modify the code to the accepted answer:

public static <T> T convertInstanceOfObject(Object o, Class<T> clazz) {
        try {
            return clazz.cast(o);
        } catch (ClassCastException e) {
            return null;
        }
    }
    public static void main(String[] args) {
        String k = convertInstanceOfObject(345435.34, String.class);
        System.out.println(k);
    }

The corresponding byte code is:

public static <T> T convertInstanceOfObject(java.lang.Object, java.lang.Class<T>);
    Code:
       0: aload_1
       1: aload_0
       2: invokevirtual #2                  // Method java/lang/Class.cast:(Ljava/lang/Object;)Ljava/lang/Object;
       5: areturn
       6: astore_2
       7: aconst_null
       8: areturn
    Exception table:
       from    to  target type
           0     5     6   Class java/lang/ClassCastException

  public static void main(java.lang.String[]);
    Code:
       0: ldc2_w        #4                  // double 345435.34d
       3: invokestatic  #6                  // Method java/lang/Double.valueOf:(D)Ljava/lang/Double;
       6: ldc           #7                  // class java/lang/String
       8: invokestatic  #8                  // Method convertInstanceOfObject:(Ljava/lang/Object;Ljava/lang/Class;)Ljava/lang/Object;
      11: checkcast     #7                  // class java/lang/String
      14: astore_1
      15: getstatic     #9                  // Field java/lang/System.out:Ljava/io/PrintStream;
      18: aload_1
      19: invokevirtual #10                 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
      22: return

Notice that there is an invokevirtual instruction in the convertInstanceOfObject method that calls Class.cast() method which throws ClassCastException which will be catch by the catch(ClassCastException e) bock and return null; hence, "null" is printed to console without any exception.


If you do not want to depend on throwing exception (which you probably should not) you can try this:

public static <T> T cast(Object o, Class<T> clazz) {
    return clazz.isInstance(o) ? clazz.cast(o) : null;
}