Cannot deserialize value of type `java.util.Date` from String

Question

Using Spring 1.5.8.RELEASE Jackson mapper giving the following exception.

Cannot deserialize value of type `java.util.Date` from String "2018-09-04T10:44:46": expected format "yyyy-MM-dd'T'HH:mm:ss.SSS" 

at [Source: UNKNOWN; line: -1, column: -1] (through reference chain: com.copart.conversationapi.calldisposition.model.vo.CallLogEntity["callEndTime"])

CallEntity.java

@JsonProperty("callEndTime") @Column(name = "call_end_ts") @JsonFormat(pattern="yyyy-MM-dd'T'HH:mm:ss.SSS") private Date callEndTime; 

DAO.java

ObjectMapper mapper = new ObjectMapper(); HashMap<String, Object> finalHashMap; finalHashMap = convertMultiToString(requestMap); mapper.enable(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY); CallLogEntity callLogEntity = mapper.convertValue(finalHashMap, CallEntity.class); 

pom.xml

<dependency>      <groupId>com.fasterxml.jackson.core</groupId>      <artifactId>jackson-databind</artifactId>      <version>2.9.0</version>      <exclusions>         <exclusion>            <groupId>com.fasterxml.jackson.core</groupId>            <artifactId>jackson-core</artifactId>         </exclusion>         <exclusion>            <groupId>com.fasterxml.jackson.core</groupId>            <artifactId>jackson-annotations</artifactId>         </exclusion>      </exclusions>   </dependency> 

Answer 1

Change your @JsonFormat line to this.

@JsonFormat(pattern="yyyy-MM-dd'T'HH:mm:ss") 

The format pattern you have right now expects the sting to have millisecond values - but your example string doesn't have them.