can two classes see each other using C++?

Question

So I have a class A, where I want to call some class B functions. So I include "b.h". But, in class B, I want to call a class A function. If I include "a.h", it ends up in an infinite loop, right? What can I do about it?

Answer 1

Put only member function declarations in header (.h) files, and put member function definitions in implementation (.cpp) files. Then your header files do not need to include each other, and you can include both headers in either implementation file.

For cases when you need to reference the other class in member signatures as well, you can use a forward declaration:

class A; 

This lets you use pointer and reference types (A* and A&), though not A itself. It also doesn't let you call members.

Example:

// a.h struct B; // forward declaration  struct A {    void foo(B* b); // pointers and references to forward-declared classes are ok };   // b.h struct A; // forward declaration  struct B {    void bar(A& a); // pointers and references to forward-declared classes are ok };   // a.cpp #include "a.h" #include "b.h"  void A::foo(B* b) {    b->bar(*this); // full declaration of B visible, ok to call members now }   // b.cpp #include "a.h" #include "b.h"  void B::bar(A& a) {    a.foo(this); // full declaration of A visible, ok to call members now }