Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Can I force jQuery Deferred/Ajax to execute fail handler after it has been resolved?

An example to make clear what i want to do. This is what I would usually do:

function success(data, status, jqxhr){
  if ( data.error )
    return failure(jqxhr, status, data.error);
  // process data
}
function failure(jqxhr, status, err){
  ...
}

$.ajax( ... )
  .done(success)
  .fail(failure)

Is there any way, i can accomplish this with anonymous functions only, like so?

   $.ajax( ... )
      .done(function(data, status, jqxhr){
         if(data.error)
            // what do i need to do here to jump in to the fail handler?
      })
      .fail(function(jqxhr, status, err){
         ...
      })
like image 482
lordvlad Avatar asked Jan 14 '14 10:01

lordvlad


Video Answer


1 Answers

what do i need to do here to jump in to the fail handler?

Don't use done, but then to map over the result of the promise. By returning a rejected promise you can "throw" an error and reject the resulting promise, so that your fail handler is executed.

$.ajax(…)
  .then(function(data, status, jqxhr){
    if (data.error)
      return $.Deferred().reject(data.error);
    else
      return data; // if you want to return multiple arguments, you'd use
                   // $.Deferred().resolve(data, status, jqxhr);
  })
  .done(function(data) {
    …
  })
  .fail(function(jqxhr, status, err){
    …
  });
like image 126
Bergi Avatar answered Sep 23 '22 21:09

Bergi