Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Can I define CellTemplate of DataGrid as a Resource so that it can be reused in multiple columns?

I want a specific template for all my columns in DataGrid. The usual method is I will replicate the entire XAML for DataTemplate multiple times in the DataGrid in each of the Column.

Is there any way I can define the CellTemplate globally as a resource and then just pass the the "Path" property of "Binding" to it, so that it displays the correct item from the DataContext ?

Is this possible ?

like image 558
teenup Avatar asked Dec 02 '11 10:12

teenup


1 Answers

Create DataTemplate in App.Xaml file with key/name.

 <DataTemplate x:Name="myTemplate" TargetType="sdk:DataGridTemplateColumn">
                <StackPanel Orientation="Horizontal">
                    <TextBox Text="{Binding FirstName}" BorderThickness="0"/>
                    <TextBox Text="{Binding LastName}" BorderThickness="0"/>
                </StackPanel>
  </DataTemplate>

Now you can use this template in DataGrid like

 <sdk:DataGridTemplateColumn Header="Name" CellTemplate={StaticResource myTemplate}>

OR
You can to pass Binding Path name in code behind like...

        string colPath = "FirstName";
        DataGrid grid = new DataGrid();
        grid.ItemsSource = myViewModel.EmpCollection;

        DataGridTemplateColumn column = new DataGridTemplateColumn();
        DataTemplate itemTemplate = (DataTemplate)XamlReader.Load("<DataTemplate xmlns=\"http://schemas.microsoft.com/client/2007\"> <ContentPresenter Content=\"{Binding Path=" + colPath + "}\"  /></DataTemplate>");

        column.CellTemplate = itemTemplate;
        grid.Columns[0] = column;

Hope this will help.

like image 108
codeSetter Avatar answered Oct 17 '22 20:10

codeSetter