C: swapping pointers in an array

Question

I have an array that contains pointers. How can I swap two pointers - say array[1] and array[4] - correctly?

Answer 1

You need a temporary variable:

void*temp = array[4];
array[4]=array[1];
array[1] = temp;

Edit Fixed first line.

Answer 2

void* temp = array[1]; 
array[1] = array[4]; 
array[4] = temp;